x.(x-2)-x+2=0 cứu………………………..

0 bình luận về “x.(x-2)-x+2=0 cứu………………………..”

1. x·(x-2)-x+2=0

   <=>x·(x-2)-(x-2)=0

   <=> (x-1)(x-2)=0

   <=>\(\left[ \begin{array}{l}x-1=0\\x-2=0\end{array} \right.\)

   <=>\(\left[ \begin{array}{l}x=1\\x=2\end{array} \right.\)

   Vậy x=1 hoặc x=2

    

   Bình luận

2. Em tham khảo:

        $x(x-2)-x+2=0$

   ⇔$x(x-2)-(x-2)=0$

   ⇔$(x-1)(x-2)=0$
   ⇔\(\left[ \begin{array}{l}x-1=0\\x-2=0\end{array} \right.\) 
   

   ⇔\(\left[ \begin{array}{l}x=1\\x=2\end{array} \right.\) 

    

   Bình luận