x·(x-2)-x+2=0 <=>x·(x-2)-(x-2)=0 <=> (x-1)(x-2)=0 <=>\(\left[ \begin{array}{l}x-1=0\\x-2=0\end{array} \right.\) <=>\(\left[ \begin{array}{l}x=1\\x=2\end{array} \right.\) Vậy x=1 hoặc x=2 Trả lời
Em tham khảo: $x(x-2)-x+2=0$ ⇔$x(x-2)-(x-2)=0$ ⇔$(x-1)(x-2)=0$⇔\(\left[ \begin{array}{l}x-1=0\\x-2=0\end{array} \right.\) ⇔\(\left[ \begin{array}{l}x=1\\x=2\end{array} \right.\) Trả lời
x·(x-2)-x+2=0
<=>x·(x-2)-(x-2)=0
<=> (x-1)(x-2)=0
<=>\(\left[ \begin{array}{l}x-1=0\\x-2=0\end{array} \right.\)
<=>\(\left[ \begin{array}{l}x=1\\x=2\end{array} \right.\)
Vậy x=1 hoặc x=2
Em tham khảo:
$x(x-2)-x+2=0$
⇔$x(x-2)-(x-2)=0$
⇔$(x-1)(x-2)=0$
⇔\(\left[ \begin{array}{l}x-1=0\\x-2=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=1\\x=2\end{array} \right.\)