-2/3.x+1/5=3/10 |x|-3/4=5/3 2/5+3/5.(x-1)=1/10 25/09/2021 Bởi Adalyn -2/3.x+1/5=3/10 |x|-3/4=5/3 2/5+3/5.(x-1)=1/10
Đáp án+Giải thích các bước giải: `a)` `-2/3.x+1/5=3/10` `\to-2/3x=3/10-1/5` `\to-2/3x=1/10` `\tox=1/10:-2/3` `\tox=-3/20` Vậy `x=-3/20` `b)` `|x|-3/4=5/3` `\to|x|=5/3+3/4` `\to|x|=29/12` `\to` \(\left[ \begin{array}{l}x=\dfrac{29}{12}\\x=-\dfrac{29}{12}\end{array} \right.\) Vậy `x\in{29/12;-29/12}` `c)` `2/5+3/5.(x-1)=1/10` `\to3/5(x-1)=1/10-2/5` `\to3/5(x-1)=-3/10` `\tox-1=-3/10:3/5` `\tox-1=-1/2` `\tox=1/2` Vậy `x=1/2` Bình luận
`-2/3.x+1/5=3/10` `-2/3.x=3/10-1/5` `-2/3.x=1/10` `x=1/10: -2/3` `x=-3/20` Vậy `x=3/(-20)` `|x|-3/4=5/3` `|x|=5/3+3/4` `|x|=29/12` Vậy `x=(-29/12;29/12)` `2/5+3/5.(x-1)=1/10` `2/5+(3(x-1))/5=1/10` `2/5+(3x-3)/5=1/10` `2/5+(3x-3)/5-2/5=1/10-2/5` `(3x-3)/5=-3/10` `3x-3=-3/2` `3x=3/2` `x=1/2` Vậy `x=1/2` Bình luận
Đáp án+Giải thích các bước giải:
`a)`
`-2/3.x+1/5=3/10`
`\to-2/3x=3/10-1/5`
`\to-2/3x=1/10`
`\tox=1/10:-2/3`
`\tox=-3/20`
Vậy `x=-3/20`
`b)`
`|x|-3/4=5/3`
`\to|x|=5/3+3/4`
`\to|x|=29/12`
`\to` \(\left[ \begin{array}{l}x=\dfrac{29}{12}\\x=-\dfrac{29}{12}\end{array} \right.\)
Vậy `x\in{29/12;-29/12}`
`c)`
`2/5+3/5.(x-1)=1/10`
`\to3/5(x-1)=1/10-2/5`
`\to3/5(x-1)=-3/10`
`\tox-1=-3/10:3/5`
`\tox-1=-1/2`
`\tox=1/2`
Vậy `x=1/2`
`-2/3.x+1/5=3/10`
`-2/3.x=3/10-1/5`
`-2/3.x=1/10`
`x=1/10: -2/3`
`x=-3/20`
Vậy `x=3/(-20)`
`|x|-3/4=5/3`
`|x|=5/3+3/4`
`|x|=29/12`
Vậy `x=(-29/12;29/12)`
`2/5+3/5.(x-1)=1/10`
`2/5+(3(x-1))/5=1/10`
`2/5+(3x-3)/5=1/10`
`2/5+(3x-3)/5-2/5=1/10-2/5`
`(3x-3)/5=-3/10`
`3x-3=-3/2`
`3x=3/2`
`x=1/2`
Vậy `x=1/2`