x^2-(x+3)(2x-11)=9 giúp mình với mình đang cần gấp!! 12/11/2021 Bởi Amara x^2-(x+3)(2x-11)=9 giúp mình với mình đang cần gấp!!
`x^2-(x+3)(2x-11)=9` `<=> x^2-(2x^2-11x+6x-33)=9` `<=> x^2-2x^2+5x+33=9` `<=> -x^2+5x+33=9` `<=> x^2-5x-24=0` `<=> x^2-8x+3x-24=0` `<=> (x-8)(x+3)=0` `<=>`\(\left[ \begin{array}{l}x-8=0\\x+3=0\end{array} \right.\) `<=>`\(\left[ \begin{array}{l}x=8\\x=-3\end{array} \right.\) Vậy `S={8;-3}` Bình luận
$x²-(x+3)(2x-11)=9$ $<=> x² -(2x²-11x+6x-33) -9=0$ $<=> x²-2x²+11x-6x+33-9=0$ $<=> -x²+5x+24=0$ $<=> -x²+8x-3x+24=0$ $<=> -x(x+8)-3(x+8)=0$ $<=> (-x-3)(x+8)=0$ $<=>$ \(\left[ \begin{array}{l}x=-3\\x=-8\end{array} \right.\) $@mocmoc756$ Bình luận
`x^2-(x+3)(2x-11)=9`
`<=> x^2-(2x^2-11x+6x-33)=9`
`<=> x^2-2x^2+5x+33=9`
`<=> -x^2+5x+33=9`
`<=> x^2-5x-24=0`
`<=> x^2-8x+3x-24=0`
`<=> (x-8)(x+3)=0`
`<=>`\(\left[ \begin{array}{l}x-8=0\\x+3=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=8\\x=-3\end{array} \right.\)
Vậy `S={8;-3}`
$x²-(x+3)(2x-11)=9$
$<=> x² -(2x²-11x+6x-33) -9=0$
$<=> x²-2x²+11x-6x+33-9=0$
$<=> -x²+5x+24=0$
$<=> -x²+8x-3x+24=0$
$<=> -x(x+8)-3(x+8)=0$
$<=> (-x-3)(x+8)=0$
$<=>$ \(\left[ \begin{array}{l}x=-3\\x=-8\end{array} \right.\)
$@mocmoc756$