(x^2-y^2)^3 (-x-3)^3 (x-3y)^3 (x^2-1 phần 2xy^2)^3 25-x^2 4x^2-y^2 giúp mình vói mình sẽ vote 5 sao 28/08/2021 Bởi Charlie (x^2-y^2)^3 (-x-3)^3 (x-3y)^3 (x^2-1 phần 2xy^2)^3 25-x^2 4x^2-y^2 giúp mình vói mình sẽ vote 5 sao
(x²-y²)³ =x$^6$-3x²y+3xy²-y³ (-x-3)³ =-(x+3)³ =-x³-9x²-27x-27 (x-3y)³ =x³-9x²y+27xy²-27y³ (x²-1 / 2xy$^2$)$^3$ =x$^6$-3 / 2x³y$^2$+3/4x²y$^4$-1/8x³y$^6$ 25-x² =(5-x)(5+x) 4x²-y² =(2x-y)(2x+y) Chúc bạn thi tốt Bình luận
`(x^2-y^2)^3` `=x^6-3x^4y^2+3x^2y^4-y^6` `(-x-3)^3` `=-x^3-9x^2-27x-27` `(x-3y)^3` `=x^3-9x^2y+27xy^2-27y^3` `((x^2-1)/(2xy^2))^3` `=(x^6-3x^4+3x^2-1)/(8x^3y^6)` `25-x^2` `=(5-x)(5+x)` `4x^2-y^2` `=(2x-y)(2x+y)` Bình luận
(x²-y²)³
=x$^6$-3x²y+3xy²-y³
(-x-3)³
=-(x+3)³
=-x³-9x²-27x-27
(x-3y)³
=x³-9x²y+27xy²-27y³
(x²-1 / 2xy$^2$)$^3$
=x$^6$-3 / 2x³y$^2$+3/4x²y$^4$-1/8x³y$^6$
25-x²
=(5-x)(5+x)
4x²-y²
=(2x-y)(2x+y)
Chúc bạn thi tốt
`(x^2-y^2)^3`
`=x^6-3x^4y^2+3x^2y^4-y^6`
`(-x-3)^3`
`=-x^3-9x^2-27x-27`
`(x-3y)^3`
`=x^3-9x^2y+27xy^2-27y^3`
`((x^2-1)/(2xy^2))^3`
`=(x^6-3x^4+3x^2-1)/(8x^3y^6)`
`25-x^2`
`=(5-x)(5+x)`
`4x^2-y^2`
`=(2x-y)(2x+y)`