Toán x^2-y^2-x+y ax^2+ay-bx^2-by 4x(x-2y)+16y^2-8xy y^2(x^2+y)-zx^2-zy 11/08/2021 By aihong x^2-y^2-x+y ax^2+ay-bx^2-by 4x(x-2y)+16y^2-8xy y^2(x^2+y)-zx^2-zy
Đáp án: °x^2 -y^2-x+y =(x^2-x)-(y^2-y) =x(x-1)-y(y-1) °ax^2+ay-bx^2-by =(ax^2-bx^2)+(ay-by) =x^2(a-b)+y(a-b) =(a-b)(x^2+y) °4x^(x-2y)+16y^2-8xy =4x^2-8xy+16y^2-8xy =4x^2+16y^2-16xy °y^2(x^2+y)-zx^2-xy =x^2y^2 +y^3-zx^2-xy =x^2(y^2-z)+y(y^2-x) Trả lời
Đáp án: $a)(x-y)(x+y-1)$ $b)(a-b)(x^2+y)$ $c)4(x-2y)^2$ $d)(y^2-x)(x^2+y)$ Giải thích các bước giải: $a)x^2-y^2-x+y$ $=(x-y)(x+y)-(x-y)$ $=(x-y)(x+y-1)$ $b)ax^2+ay-bx^2-by$ $=a(x^2+y)-b(x^2+y)$ $=(a-b)(x^2+y)$ $c)4x(x-2y)+16y^2-8xy$ $=4x^2-8xy+16y^2-8xy$ $=4x^2-16xy+16y^2$ $=4(x-2y)^2$ $d)y^2(x^2+y)-x^2z-yz$ $=y^2(x^2+y)-z(x^2+y)$ $=(y^2-x)(x^2+y)$ Trả lời
Đáp án:
°x^2 -y^2-x+y
=(x^2-x)-(y^2-y)
=x(x-1)-y(y-1)
°ax^2+ay-bx^2-by
=(ax^2-bx^2)+(ay-by)
=x^2(a-b)+y(a-b)
=(a-b)(x^2+y)
°4x^(x-2y)+16y^2-8xy
=4x^2-8xy+16y^2-8xy
=4x^2+16y^2-16xy
°y^2(x^2+y)-zx^2-xy
=x^2y^2 +y^3-zx^2-xy
=x^2(y^2-z)+y(y^2-x)
Đáp án: $a)(x-y)(x+y-1)$
$b)(a-b)(x^2+y)$
$c)4(x-2y)^2$
$d)(y^2-x)(x^2+y)$
Giải thích các bước giải:
$a)x^2-y^2-x+y$
$=(x-y)(x+y)-(x-y)$
$=(x-y)(x+y-1)$
$b)ax^2+ay-bx^2-by$
$=a(x^2+y)-b(x^2+y)$
$=(a-b)(x^2+y)$
$c)4x(x-2y)+16y^2-8xy$
$=4x^2-8xy+16y^2-8xy$
$=4x^2-16xy+16y^2$
$=4(x-2y)^2$
$d)y^2(x^2+y)-x^2z-yz$
$=y^2(x^2+y)-z(x^2+y)$
$=(y^2-x)(x^2+y)$