(2000² – 2010) (2004² + 4005) 2005 B= ______________________________________ 2001.2003.2006.2007

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1. Đáp án: $ B=\dfrac{4007984975}{2007003}$

   Giải thích các bước giải:

   Ta có:

   $B=\dfrac{(2000^2-2010)(2004^2+4005)\cdot 2005}{2001\cdot 2003\cdot 2006\cdot 2007}$

   $\to B=\dfrac{(2000^2-2010)(2004^2+2\cdot 2004-3)\cdot 2005}{2001\cdot 2003\cdot 2006\cdot 2007}$

   $\to B=\dfrac{(2000^2-2010)(2004^2+3\cdot 2004-2004-3)\cdot 2005}{2001\cdot 2003\cdot 2006\cdot 2007}$

   $\to B=\dfrac{(2000^2-2010)(2004(2004+3)-(2004+3))\cdot 2005}{2001\cdot 2003\cdot 2006\cdot 2007}$

   $\to B=\dfrac{(2000^2-2010)((2004-1)(2004+3))\cdot 2005}{2001\cdot 2003\cdot 2006\cdot 2007}$

   $\to B=\dfrac{(2000^2-2010)\cdot 2003\cdot 2007\cdot 2005}{2001\cdot 2003\cdot 2006\cdot 2007}$

   $\to B=\dfrac{(2000^2-2010)\cdot 2005}{2001\cdot 2006}$

   $\to B=\dfrac{3997990\cdot 2005}{2001\cdot 2006}$

   $\to B=\dfrac{1998995\cdot 2005}{2001\cdot 1003}$

   $\to B=\dfrac{4007984975}{2007003}$

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