(x/2021-1) + (x/2020-2) + (x/2019-3) = (x/2018 -4) 29/07/2021 Bởi Arianna (x/2021-1) + (x/2020-2) + (x/2019-3) = (x/2018 -4)
Giải thích các bước giải: `(x/2021 – 1) + (x/2020 – 2) + (x/2019 – 3) = (x/2018 – 4)` `=> (x-2022)/2021 + (x-2022)/2020 + (x-2022)/2019 = (x-2022)/2018` `=> (x-2022)/2021 + (x-2022)/2020 + (x-2022)/2019- (x-2022)/2018 = 0` `=> (x-2022).(1/2021 + 1/2020 + 1/2019 – 1/2018)=0` `=> x-2022 = 0` `=> x=2022` Bình luận
Giải thích các bước giải:
`(x/2021 – 1) + (x/2020 – 2) + (x/2019 – 3) = (x/2018 – 4)`
`=> (x-2022)/2021 + (x-2022)/2020 + (x-2022)/2019 = (x-2022)/2018`
`=> (x-2022)/2021 + (x-2022)/2020 + (x-2022)/2019- (x-2022)/2018 = 0`
`=> (x-2022).(1/2021 + 1/2020 + 1/2019 – 1/2018)=0`
`=> x-2022 = 0`
`=> x=2022`