295-(31-2².5)² 205-[1200-(4²-2.3)³]:40 107-{38+[7.3²-24:6+(9-7)³]}:15

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1. \(\begin{array}{l}
    + )\,\,295 – {\left( {31 – {2^2}.5} \right)^2}\\
    = 295 – {\left( {31 – 4.5} \right)^2} = 295 – {\left( {31 – 20} \right)^2}\\
    = 295 – {11^2} = 295 – 121 = 174\\
    + )\,205 – \left[ {1200 – {{\left( {{4^2} – 2.3} \right)}^3}} \right]:40\\
    = 205 – \left[ {1200 – {{\left( {16 – 6} \right)}^3}} \right]:40\\
    = 205 – \left( {1200 – {{10}^3}} \right):40\\
    = 205 – \left( {1200 – 1000} \right):40\\
    = 204 – 200:5\\
    = 204 – 4 = 200\\
    + )\,\,107 – \left\{ {38 + \left[ {{{7.3}^2} – 24:6 + {{\left( {9 – 7} \right)}^3}} \right]} \right\}:15\\
    = 107 – \left\{ {38 + \left[ {7.9 – 24:6 + {2^3}} \right]} \right\}:15\\
    = 107 – \left[ {38 + \left( {63 – 4 + 8} \right)} \right]:15\\
    = 107 – \left( {38 + 67} \right):15\\
    = 107 – 105:15\\
    = 107 – 7 = 100
   \end{array}\)

    

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2. Đáp án:

    

   Giải thích các bước giải:

    295-(31-2^2.5)^2=295-(31-20)^2

   =295-11^2=174

   205-(1200-(4^2-2.3)^3)):40=

   205-(1200-(16-6)^3)):40=

   205-(1200-10^3):40

   =205-200:40=200

   107-(38+(7.3^2-24:6+(9-7)^3)):15=

   107-(38+(63-4+8)):15=107-105:15=100

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