2XY-X+Y=-5 AI TRẢ LỜI ĐÀU TIÊN CHO 60 DIỂM VOTE HAY NHẤT 05/07/2021 Bởi Piper 2XY-X+Y=-5 AI TRẢ LỜI ĐÀU TIÊN CHO 60 DIỂM VOTE HAY NHẤT
Đáp án: `2xy – x + y = -5 (x,y ∈ ZZ)` `↔2 (2xy – x + y) = -5 × 2` `↔ 4xy – 2x + 2y = -10` `↔ 4xy – 2x + 2y – 1 = -10 – 1` `↔ (4xy – 2x) + (2y – 1) = -11` `↔ 2x (2y – 1) + (2y – 1) =-11` `↔ (2x + 1) (2y-1) = -11` Ta có bảng : $\begin{array}{|c|c|c|c|c|c|c|}\hline 2x+1& -1 & 11 & 1 & -11\\\hline 2y-1& 11 & -1 & -11 & 1 \\\hline x & -1&5&0&-6\\\hline y & 6&0&-5&1 \\\hline\end{array}$ Vậy cặp `(x;y)` nguyên là : `(-1;6), (0;5), (0;-5), (-6;1)` Bình luận
Đáp án:Thiếu `x,y in ZZ` `2xy-x+y=-5` `=>x(2y-1)+y=-5` `=>2x(2y-1)+2y=-10` `=>2x(2y-1)+2y-1=-11` `=>(2y-1)(2x+1)=-11` Vì `x,y in ZZ` `=>2y-1,2x+1 in ZZ` `=>2y-1,2x+1 in Ư(-11)={+-1,+-11]` `TH1:2y-1=1,2x+1=-11` `=>2y=2,2x=-12` `=>y=1,x=-6(tm)` `TH2:2y-1=-1,2x+1=11` `=>2y=0,2x=10` `=>y=0,x=5(tm)` `TH3:2y-1=-11,2x+1=1` `=>2y=-10,2x=0` `=>y=-5,x=0(tm)` `TH4:2y-1=11,2x+1=-1` `=>2y=12,2x=-2` `=>y=6,x=-1(tm)` Vậy `(x,y) in {(-6,1),(5,0),(0,-5),(-1,6)}`. Bình luận
Đáp án:
`2xy – x + y = -5 (x,y ∈ ZZ)`
`↔2 (2xy – x + y) = -5 × 2`
`↔ 4xy – 2x + 2y = -10`
`↔ 4xy – 2x + 2y – 1 = -10 – 1`
`↔ (4xy – 2x) + (2y – 1) = -11`
`↔ 2x (2y – 1) + (2y – 1) =-11`
`↔ (2x + 1) (2y-1) = -11`
Ta có bảng :
$\begin{array}{|c|c|c|c|c|c|c|}\hline 2x+1& -1 & 11 & 1 & -11\\\hline 2y-1& 11 & -1 & -11 & 1 \\\hline x & -1&5&0&-6\\\hline y & 6&0&-5&1 \\\hline\end{array}$
Vậy cặp `(x;y)` nguyên là : `(-1;6), (0;5), (0;-5), (-6;1)`
Đáp án:Thiếu `x,y in ZZ`
`2xy-x+y=-5`
`=>x(2y-1)+y=-5`
`=>2x(2y-1)+2y=-10`
`=>2x(2y-1)+2y-1=-11`
`=>(2y-1)(2x+1)=-11`
Vì `x,y in ZZ`
`=>2y-1,2x+1 in ZZ`
`=>2y-1,2x+1 in Ư(-11)={+-1,+-11]`
`TH1:2y-1=1,2x+1=-11`
`=>2y=2,2x=-12`
`=>y=1,x=-6(tm)`
`TH2:2y-1=-1,2x+1=11`
`=>2y=0,2x=10`
`=>y=0,x=5(tm)`
`TH3:2y-1=-11,2x+1=1`
`=>2y=-10,2x=0`
`=>y=-5,x=0(tm)`
`TH4:2y-1=11,2x+1=-1`
`=>2y=12,2x=-2`
`=>y=6,x=-1(tm)`
Vậy `(x,y) in {(-6,1),(5,0),(0,-5),(-1,6)}`.