x-y/8 + 2y/8 X^2-x/xy + 1-4y/xy 5xy-4y/2x^2y^3 + 3xy + 4y/2x^2y^3 X+1/a-b + x+1/a-b + x+3/a-b 2x^2-xy/xy + xy+y^2/y-x + 2y^2-x^2/x-y Giúp mik với

By Brielle

x-y/8 + 2y/8
X^2-x/xy + 1-4y/xy
5xy-4y/2x^2y^3 + 3xy + 4y/2x^2y^3
X+1/a-b + x+1/a-b + x+3/a-b
2x^2-xy/xy + xy+y^2/y-x + 2y^2-x^2/x-y
Giúp mik với

0 bình luận về “x-y/8 + 2y/8 X^2-x/xy + 1-4y/xy 5xy-4y/2x^2y^3 + 3xy + 4y/2x^2y^3 X+1/a-b + x+1/a-b + x+3/a-b 2x^2-xy/xy + xy+y^2/y-x + 2y^2-x^2/x-y Giúp mik với”

  1. $\frac{x-y}{8}+\frac{2y}{8}$

    = $\frac{x-y+2y}{8}$

    = $\frac{x+y}{8}$

    $\frac{x²-x}{xy}+\frac{1-4y}{xy}$

    = $\frac{x²-x+1-4y}{xy}$

    $\frac{5xy-4y}{2x².2y³}+\frac{3xy+4y}{2x².2y³}$

    = $\frac{5xy-4y+3xy+4y}{2x².2y³}$

    = $\frac{8xy}{2x².2y³}$

    = $\frac{2}{xy²}$

    $\frac{x+1}{a-b}+\frac{x+1}{a-b}+\frac{x+3}{a-b}$

    = $\frac{x+1+x+1+x+3}{a-b}$

    = $\frac{3x+5}{a-b}$

    Trả lời
  2. `(x-y)/8 + (2y)/8=(x-y+2y)/8=(x-y)/8`

    `(x^2-x)/(xy) + (1-4y)/(xy)=(x^2-x+1-4y)/(xy)`

    `(5xy-4y)/(2x^2y^3) + (3xy + 4y)/(2x^2y^3)=(5xy-4y+3xy+4y)/(2x^2y^3)=(8xy)/(2x^2y^3)`

    `(x+1)/(a-b) + (x+1)/(a-b) + (x+3)/(a-b)=(x+1+x+1+x+3)/(a-b)=(3x+5)/(a-b)`

    `(2x^2-xy)/(x-y) + (xy+y^2)/(x-y) + (2y^2-x^2)/(x-y)=(2x^2-xy+xy+y^2+2xy^2-x^2)/(x-y)=(x^2+y^2+2xy^2)/(x-y)`

    Trả lời

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