3 1 2 5 1 7 1 1 _ x + _ = 1 – x – – = – – x – – = –

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1. $\frac{3}5x+\frac{1}4=1$

   $⇔\frac{3}5x=1-\frac{1}4$

   $⇔\frac{3}5x=\frac{3}4$

   $⇔x=\frac{3}4÷\frac{3}5=\frac{5}4$

   Vậy x=5/4

   $\frac{2}3x-\frac{5}6=\frac{1}2$

   $⇔\frac{2}3x=\frac{1}2+\frac{5}6$

   $⇔\frac{2}3x=\frac{4}3$

   $⇔x=\frac{4}3÷\frac{2}3=2$

   Vậy x=2

   $\frac{7}2x-\frac{1}4=\frac{1}3$

   $⇔\frac{7}2x=\frac{1}3+\frac{1}4$

   $⇔\frac{7}2x=\frac{7}{12}$

   $⇔x=\frac{7}{12}÷\frac{7}2=\frac{1}6$

   Vậy x=1/6

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2. Đáp án:

    

   Giải thích các bước giải:

   a) 3/5 .x+1/4=1

   3/5 .x=1-1/4

   3/5 .x=3/4

   x=3/4 : 3/5

   x=3/4.5/3

   x=5/4

   b) 2/3 .x -5/6=1/2

   2/3 .x =3/6+5/6

   2/3 .x=3/2

   x=3/2:2/3

   x=3/2.3/2

   x=9/4

   c)7/2 .x -1/4=1/3

   7/2. x=4/12+3/12

   7/2 .x=7/12

   x=7/12:7/2

   x=7/12.2/7

   x=1/6

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