(3x+1)(x-5)=(2x-5)=(2x-6)(3x+1) làm thế nào

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1. $(3x+1)(x-5)=(2x-6)(3x+1)$

   $⇔(3x+1)(x-5)-(2x-6)(3x+1)=0$
   $⇔(3x+1)(x-5-2x+6)=0$

   $⇔(3x+1)(-x+1)=0$

   $⇔$ \(\left[ \begin{array}{l}3x+1=0\\-x+1=0\end{array} \right.\) 

   $⇔$ \(\left[ \begin{array}{l}x=-1/3\\x=1\end{array} \right.\) 

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