3x^2*(x^2-2x+6) X*(y-3)*(y+3) (-2x^5+3x^2-4x^3):2x^2 28/11/2021 Bởi Hadley 3x^2*(x^2-2x+6) X*(y-3)*(y+3) (-2x^5+3x^2-4x^3):2x^2
`3x^2(x^2-2x+6)` `=3x^(2).x^2+3x^2.(-2x)+3x^(2).6` `=3x^4-6x^3+18x^2` `x(y-3)(y+3)` `=x(y^2-3^2)` `=x.(y^2-9)` `=xy^2-9x` `(-2x^5+3x^2-4x^3):2x^2` `=(-2x^5:2x^2)+(3x^2:2x^2)-(4x^3:2x^2)` `=-x^3+3/2-2x` Bình luận
`3x^2(x^2-2x+6)`
`=3x^(2).x^2+3x^2.(-2x)+3x^(2).6`
`=3x^4-6x^3+18x^2`
`x(y-3)(y+3)`
`=x(y^2-3^2)`
`=x.(y^2-9)`
`=xy^2-9x`
`(-2x^5+3x^2-4x^3):2x^2`
`=(-2x^5:2x^2)+(3x^2:2x^2)-(4x^3:2x^2)`
`=-x^3+3/2-2x`