(3x – 2^4). 7 ^ 3 = 2 . 7^4 x – [ 42 + (-28)] = -8 Ix-3I=I5I + I-7I g) 4- ( 7 – x) = x – (13-4)

0 bình luận về “(3x – 2^4). 7 ^ 3 = 2 . 7^4 x – [ 42 + (-28)] = -8 Ix-3I=I5I + I-7I g) 4- ( 7 – x) = x – (13-4)”

1. 1/ (3x- 2^4). 7³=2. 7^4

   (3x- 16). 343= 4802

    3x- 16=4802 :343= 14

   3x= 14+16=30

   x= 30: 3=10

   2/ x-[42+(-28)]=-8

   x-14=-8

   x=(-8)+14

   x=6

   3/ |x-3|=|5|+|-7|

   |x-3|=5+7=12

   x-3=±12

   TH1:                                         TH2:

   x-3=12                                      x-3=-12

   x=12+3=15                              x=(-12)+3=-11

   Vậy x∈ {15; -11}

   4/ 4-(7-x)=x-(13-4)

   4-7+x=x-9

   (-3)+x=x-9

   2x=3+9

   2x=12

   x=12:2

   x=6

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