3x ( x – 2 ) – 5x (1 – x) – 8 ( x2 – 3 ) 12/07/2021 Bởi Lydia 3x ( x – 2 ) – 5x (1 – x) – 8 ( x2 – 3 )
`3x . ( x – 2 ) – 5x . ( 1 – x ) – 8 . ( x^2 – 3 )` `⇒ (3x)^2 – 6x – 5x . (- x + 1 ) – 8 . ( x^2 – 3 )` `⇒ (3x)^2 – 6x + (5x)^2 – 5x – (8x)^2 + 24 ` `⇒ -(6x) – 5x + 24` `⇒ -11x + 24` Bình luận
`3x(x – 2) – 5x(1 – x) – 8(x^2 – 3)` `= 3x. x – 3x. 2 – 5x + 5x. x – 8. x^2 + 8. 3` `= 3x^2 – 6x – 5x + 5x^2 – 8x^2 + 24` `= (3x^2 + 5x^2 – 8x^2) – (6x + 5x) + 24` `= -11x + 24` Bình luận
`3x . ( x – 2 ) – 5x . ( 1 – x ) – 8 . ( x^2 – 3 )`
`⇒ (3x)^2 – 6x – 5x . (- x + 1 ) – 8 . ( x^2 – 3 )`
`⇒ (3x)^2 – 6x + (5x)^2 – 5x – (8x)^2 + 24 `
`⇒ -(6x) – 5x + 24`
`⇒ -11x + 24`
`3x(x – 2) – 5x(1 – x) – 8(x^2 – 3)`
`= 3x. x – 3x. 2 – 5x + 5x. x – 8. x^2 + 8. 3`
`= 3x^2 – 6x – 5x + 5x^2 – 8x^2 + 24`
`= (3x^2 + 5x^2 – 8x^2) – (6x + 5x) + 24`
`= -11x + 24`