(x-3)-x^2+9=0 Giúp mik vs mik đag cần gấp ạ Hứa vote 5⭐️

Đáp án:

 $(x-3)-x^2+9=0$

$⇔(x-3)-(x^2-9)=0$

$⇔(x-3)-(x+3)(x-3)=0$

$⇔(x-3)(x+3-1)=0$

$⇔(x-3)(x+2)=0$

$⇔$\(\left[ \begin{array}{l}x-3=0\\x+2=0\end{array} \right.\) 

$⇔$\(\left[ \begin{array}{l}x=3\\x=-2\end{array} \right.\) 

$\text{Vậy x ∈ {3 ;-2}}$