x^3+3x^2+3x+1-27z^3 x^4+x^3+x+1 X^2-x^3-x^2+1 phân tích hộ mk 09/07/2021 Bởi Arya x^3+3x^2+3x+1-27z^3 x^4+x^3+x+1 X^2-x^3-x^2+1 phân tích hộ mk
Đáp án: `x^3+3x^2+3x+1-27z^3=(x-3z+1)(x^2+2x+1+3xz+3z+9z^2)` `x^4+x^3+x+1=(x+1)^2(x^2-x+1)` `x^2-x^3-x^2+1=(1-x)(x^2+x+1)` Giải thích các bước giải: `x^3+3x^2+3x+1-27z^3=(x+1)^3-(9z)^3=(x+1-3z)[(x+1)^2+(x+1)3z+9z^2]` `=(x-3z+1)(x^2+2x+1+3xz+3z+9z^2)` `x^4+x^3+x+1=x^3(x+1)+(x+1)=(x+1)(x^3+1)=(x+1)^2(x^2-x+1)` `x^2-x^3-x^2+1=-x^3+1=-(x^3-1)=-(x-1)(x^2+x+1)=(1-x)(x^2+x+1)` Bình luận
Các bước giải: `x³ +3x² +3x +1 -27z³` `= (x +1)³ -27z³` `= (x +1 -3z).(x² +2x +1 +3zx +3z +9z²)` —————- `x^4 +x^3 +x +1` `= x^3.(x +1) +(x +1)` `= (x +1).(x^3 +1)` `= (x +1).(x +1).(x² -x +1)` `= (x +1)².(x² -x +1)` —————- `x^2 -x^3 -x^2 +1` `= x².(1-x) +(1 -x).(1 +x)` `= (1 -x).(x² +1 +x)` Bình luận
Đáp án:
`x^3+3x^2+3x+1-27z^3=(x-3z+1)(x^2+2x+1+3xz+3z+9z^2)`
`x^4+x^3+x+1=(x+1)^2(x^2-x+1)`
`x^2-x^3-x^2+1=(1-x)(x^2+x+1)`
Giải thích các bước giải:
`x^3+3x^2+3x+1-27z^3=(x+1)^3-(9z)^3=(x+1-3z)[(x+1)^2+(x+1)3z+9z^2]`
`=(x-3z+1)(x^2+2x+1+3xz+3z+9z^2)`
`x^4+x^3+x+1=x^3(x+1)+(x+1)=(x+1)(x^3+1)=(x+1)^2(x^2-x+1)`
`x^2-x^3-x^2+1=-x^3+1=-(x^3-1)=-(x-1)(x^2+x+1)=(1-x)(x^2+x+1)`
Các bước giải:
`x³ +3x² +3x +1 -27z³`
`= (x +1)³ -27z³`
`= (x +1 -3z).(x² +2x +1 +3zx +3z +9z²)`
—————-
`x^4 +x^3 +x +1`
`= x^3.(x +1) +(x +1)`
`= (x +1).(x^3 +1)`
`= (x +1).(x +1).(x² -x +1)`
`= (x +1)².(x² -x +1)`
—————-
`x^2 -x^3 -x^2 +1`
`= x².(1-x) +(1 -x).(1 +x)`
`= (1 -x).(x² +1 +x)`