3)Tìm x a) x.(11 phần 5)mũ27 =(11 phần 5)mũ29 b) (2x-1)mũ2 = 1 phần 4

`a) x.(11/5)^{27} = (11/5)^{29}`

`<=> x = (11/5)^{29} : (11/5)^{27}`

`<=> x = (11/5)^2`

`<=> x = 121/25`

`b) (2x – 1)^2 = 1/4`

`<=> |2x – 1| = 1/2`

`<=>` \(\left[ \begin{array}{l}2x – 1 = \dfrac{1}{2}\\2x – 1 = -\dfrac{1}{2}\end{array} \right.\) 

`<=>` \(\left[ \begin{array}{l}x = \dfrac{3}{4}\\x = \dfrac{1}{4}\end{array} \right.\)