(4+1)*(4*2+1)*(4*4+1)*(4*16+1) mình cần gấp 30/08/2021 Bởi Eloise (4+1)*(4*2+1)*(4*4+1)*(4*16+1) mình cần gấp
Giải thích các bước giải: $\left ( 4 + 1 \right )\left ( 4^{2} + 1 \right )\left ( 4^{4} + 1 \right )\left ( 4^{16} + 1 \right )$ $= \dfrac{1}{3}\left ( 4 – 1 \right )\left ( 4 + 1 \right )\left ( 4^{2} + 1 \right )\left ( 4^{4} + 1 \right )\left ( 4^{16} + 1 \right )$ $= \dfrac{1}{3}\left ( 4^{2} – 1 \right )\left ( 4^{2} + 1 \right )\left ( 4^{4} + 1 \right )\left ( 4^{16} + 1 \right )$ $= \dfrac{1}{3}\left ( 4^{4} – 1 \right )\left ( 4^{4} + 1 \right )\left ( 4^{16} + 1 \right )$ $= \dfrac{1}{3}\left ( 4^{16} – 1 \right )\left ( 4^{16} + 1 \right )$ $= \dfrac{1}{3}\left ( 4^{32} – 1 \right )$ Bình luận
Giải thích các bước giải:
$\left ( 4 + 1 \right )\left ( 4^{2} + 1 \right )\left ( 4^{4} + 1 \right )\left ( 4^{16} + 1 \right )$
$= \dfrac{1}{3}\left ( 4 – 1 \right )\left ( 4 + 1 \right )\left ( 4^{2} + 1 \right )\left ( 4^{4} + 1 \right )\left ( 4^{16} + 1 \right )$
$= \dfrac{1}{3}\left ( 4^{2} – 1 \right )\left ( 4^{2} + 1 \right )\left ( 4^{4} + 1 \right )\left ( 4^{16} + 1 \right )$
$= \dfrac{1}{3}\left ( 4^{4} – 1 \right )\left ( 4^{4} + 1 \right )\left ( 4^{16} + 1 \right )$
$= \dfrac{1}{3}\left ( 4^{16} – 1 \right )\left ( 4^{16} + 1 \right )$
$= \dfrac{1}{3}\left ( 4^{32} – 1 \right )$
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