4x*2-16x*2y*2+y*2+4xy x*3-16x-15x(x-4) x*5+x+1 Giúp mik vs 24/08/2021 Bởi Katherine 4x*2-16x*2y*2+y*2+4xy x*3-16x-15x(x-4) x*5+x+1 Giúp mik vs
@Holliwood#: Đáp án: a) (2x+y-4xy).(2x+y+4xy) b) x.(x-4).(x-11) c) (x²+x+1).(x³-x²+1) Giải thích các bước giải: a) 4x²-16x²y²+y²+4xy = (2x+y)²-16x²y² = (2x+y-4xy).(2x+y+4xy) b) x³-16x-15x.(x-4) = x.(x²-16-15(x-4) = x.(x²-16-15x+60) = x.(x²+44-15x) = x.(x²-15x+44) = x.(x²-4x-11x+44) = x.[x.(x-4)-11(x-4)] = x.(x-4).(x-11) c) $x^{5}$+x+1 = $x^{5}$+$x^{4}$-$x^{4}$+x³-x³-x²+x²+x+1 = x³.(x²+x+1)-x².(x²+x+1)+x²+x+1 = (x²+x+1).(x³-x²+1) Bn tham khảo nhé!!!!!!!!!!!!!!!!!!!!! Xin ctlhn ạ!!!!!!!!!!!!!!!!!!!! Bình luận
Đáp án: a) ( 2x + y – 4xy)( 2x + y + 4xy) b) x( x – 4)( x – 11) c) ( x² + x + 1)( x³ – x² + 1) Giải thích các bước giải: a) 4x² – 16x²y² + y² + 4xy = ( 4x² + 4xy + y²) – 16x²y² = ( 2x + y)² – ( 4xy)² = ( 2x + y – 4xy)( 2x + y + 4xy) b) x³ – 16x – 15x( x – 4) = ( x³ – 16x) – 15x( x – 4) = x( x² – 16) – 15x( x – 4) = x( x – 4)( x + 4) – 15x( x – 4) = ( x – 4)[x ( x + 4) – 15x] = ( x – 4)( x² + 4x – 15x) = ( x – 4)( x² – 11x) = x ( x – 4)( x -11) c) x⁵ + x + 1 = ( x⁵ + x⁴ + x³) – ( x⁴ + x³ + x² ) + ( x² + x + 1) = x³(x² + x + 1) – x²(x² + x + 1) + ( x² + x + 1) = ( x² + x + 1)( x³ – x² + 1) Bình luận
@Holliwood#:
Đáp án:
a) (2x+y-4xy).(2x+y+4xy)
b) x.(x-4).(x-11)
c) (x²+x+1).(x³-x²+1)
Giải thích các bước giải:
a) 4x²-16x²y²+y²+4xy
= (2x+y)²-16x²y²
= (2x+y-4xy).(2x+y+4xy)
b) x³-16x-15x.(x-4)
= x.(x²-16-15(x-4)
= x.(x²-16-15x+60)
= x.(x²+44-15x)
= x.(x²-15x+44)
= x.(x²-4x-11x+44)
= x.[x.(x-4)-11(x-4)]
= x.(x-4).(x-11)
c) $x^{5}$+x+1
= $x^{5}$+$x^{4}$-$x^{4}$+x³-x³-x²+x²+x+1
= x³.(x²+x+1)-x².(x²+x+1)+x²+x+1
= (x²+x+1).(x³-x²+1)
Bn tham khảo nhé!!!!!!!!!!!!!!!!!!!!!
Xin ctlhn ạ!!!!!!!!!!!!!!!!!!!!
Đáp án:
a) ( 2x + y – 4xy)( 2x + y + 4xy)
b) x( x – 4)( x – 11)
c) ( x² + x + 1)( x³ – x² + 1)
Giải thích các bước giải:
a) 4x² – 16x²y² + y² + 4xy
= ( 4x² + 4xy + y²) – 16x²y²
= ( 2x + y)² – ( 4xy)²
= ( 2x + y – 4xy)( 2x + y + 4xy)
b) x³ – 16x – 15x( x – 4)
= ( x³ – 16x) – 15x( x – 4)
= x( x² – 16) – 15x( x – 4)
= x( x – 4)( x + 4) – 15x( x – 4)
= ( x – 4)[x ( x + 4) – 15x]
= ( x – 4)( x² + 4x – 15x)
= ( x – 4)( x² – 11x)
= x ( x – 4)( x -11)
c) x⁵ + x + 1
= ( x⁵ + x⁴ + x³) – ( x⁴ + x³ + x² ) +
( x² + x + 1)
= x³(x² + x + 1) – x²(x² + x + 1) +
( x² + x + 1)
= ( x² + x + 1)( x³ – x² + 1)