Toán (4/9)^x=(8/27)^6 (4/9)^x(8/27)^10 giúp mình vs 15/07/2021 By Josie (4/9)^x=(8/27)^6 (4/9)^x(8/27)^10 giúp mình vs
a) `(4/9)^x=(8/27)^6` `↔(4/9)^x=[(2/3)^3]^2` `↔(4/9)^x=[(2/3)^2]^3` `↔(4/9)^x=(4/9)^3` `↔x=3` b) `(4/9)^x=(8/27)^{10}` `↔(4/9)^x=[(2/3)^3]^{10}` `↔(4/9)^x=[(2/3)^2]^{15}` `↔(4/9)^x=(4/9)^{15}` `↔x=15` Trả lời
`(4/9)^x=(8/27)^6` `(4/9)^x=[(2/3)^3]^6` `(4/9)^x=(2/3)^18` `(4/9)^x=[(2/3)^2]^9` `(4/9)^x=(4/9)^9` `=>x=9` `(4/9)^x=(8/27)^10` `(4/9)^x=[(2/3)^3]^10` `(4/9)^x=(2/3)^30` `(4/9)^x=[(2/3)^2]^15` `(4/9)^x=(4/9)^15` `=>x=15` CHÚC BẠN HỌC TỐT!!! Trả lời
a) `(4/9)^x=(8/27)^6`
`↔(4/9)^x=[(2/3)^3]^2`
`↔(4/9)^x=[(2/3)^2]^3`
`↔(4/9)^x=(4/9)^3`
`↔x=3`
b) `(4/9)^x=(8/27)^{10}`
`↔(4/9)^x=[(2/3)^3]^{10}`
`↔(4/9)^x=[(2/3)^2]^{15}`
`↔(4/9)^x=(4/9)^{15}`
`↔x=15`
`(4/9)^x=(8/27)^6`
`(4/9)^x=[(2/3)^3]^6`
`(4/9)^x=(2/3)^18`
`(4/9)^x=[(2/3)^2]^9`
`(4/9)^x=(4/9)^9`
`=>x=9`
`(4/9)^x=(8/27)^10`
`(4/9)^x=[(2/3)^3]^10`
`(4/9)^x=(2/3)^30`
`(4/9)^x=[(2/3)^2]^15`
`(4/9)^x=(4/9)^15`
`=>x=15`
CHÚC BẠN HỌC TỐT!!!