(4/9)^x=(8/27)^6 (4/9)^x(8/27)^10 giúp mình vs

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1. a) `(4/9)^x=(8/27)^6`

   `↔(4/9)^x=[(2/3)^3]^2`

   `↔(4/9)^x=[(2/3)^2]^3`

   `↔(4/9)^x=(4/9)^3`

   `↔x=3`

   b) `(4/9)^x=(8/27)^{10}`

   `↔(4/9)^x=[(2/3)^3]^{10}`

   `↔(4/9)^x=[(2/3)^2]^{15}`

   `↔(4/9)^x=(4/9)^{15}`

   `↔x=15`

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2. `(4/9)^x=(8/27)^6`

   `(4/9)^x=[(2/3)^3]^6`

   `(4/9)^x=(2/3)^18`

   `(4/9)^x=[(2/3)^2]^9`

   `(4/9)^x=(4/9)^9`

   `=>x=9`

   `(4/9)^x=(8/27)^10`

   `(4/9)^x=[(2/3)^3]^10`

   `(4/9)^x=(2/3)^30`

   `(4/9)^x=[(2/3)^2]^15`

   `(4/9)^x=(4/9)^15`

   `=>x=15`

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