√49+√25-4√0,25 = (√109 – √121 – √81): √0,49= √1/9 . √0,81.√0,09= 3/5 .√16 + 2. √16/25

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1. ` \sqrt49 + \sqrt25 – 4\sqrt(0,25)`

   `= 7 + 5 – 2`

   `= 10`

   `(\sqrt109 – \sqrt121 – \sqrt81) : \sqrt(0,49)`

   `= (\sqrt109 – 11 – 9) : 0,7`

   `= (\sqrt109 – 20) : 0,7`

   `= (10\sqrt109)/7 – 200/7`

   `= (10\sqrt109 – 200)/7`

   `\sqrt(1/9) . \sqrt(0,81) . \sqrt(0,09)`

   `= 1/3 . 0,9 . 0,3`

   `= 0,09`

   `3/5 . \sqrt16 + 2\sqrt(16/25)`

   `= 3/5 . 4 + 2. 4/5`

   `= 12/5 + 8/5`

   `= 4`

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2. $\sqrt{49}+\sqrt{25}-4.\sqrt{0,25}$

   $= 7+5-4.0,5$

   $= 7+5-2=10$

   $(\sqrt{109}-\sqrt{121}-\sqrt{81}):\sqrt{0,49}$

   $=(\sqrt{109}-11-9):0,7$

   $= (\sqrt{109}-20):0,7$

   $= \dfrac{10(\sqrt{109}-20)}{7}$

   $\sqrt{\frac{1}{9}}.\sqrt{0,81}.\sqrt{0,09}$

   $=\frac{1}{3}.0,9.0,3$

   $= 0,09$

   $\frac{3}{5}.\sqrt{16}+2\sqrt{\frac{16}{25}}$

   $=\frac{3}{5}.4+2.\frac{4}{5}$

   $=\frac{12}{5}+\frac{8}{5}$

   $=4$

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