(5x+2)(x+10)+(5x–2)(x–10)x2−100 —————————————————- (x-10)(x+10) 13/11/2021 Bởi Arianna (5x+2)(x+10)+(5x–2)(x–10)x2−100 —————————————————- (x-10)(x+10)
Đáp án: Giải thích các bước giải: $\frac{\left( 5x+2 \right)\left( x+10 \right)+\left( 5x-2 \right)\left( x-10 \right).2-100}{\left( x-10 \right)\left( x+10 \right)}$ $=\frac{5{{x}^{2}}+50x+2x+20+\left( 5{{x}^{2}}-50x-2x+20 \right).2-100}{{{x}^{2}}-100}$ $=\frac{5{{x}^{2}}+52x+20+10{{x}^{2}}-100x-4x+40-100}{{{x}^{2}}-100}$ $=\frac{15{{x}^{2}}-52x-40}{{{x}^{2}}-100}$ Bình luận
Giải thích các bước giải: $\frac{(5x+2)(x+10)+(5x–2)(x–10)x^2−100}{(x-10)(x+10)}$ =$\frac{(5x+2)(x+10)+x^2(5x−2)(x−10)−100}{(x−10)(x+10)}$ =$\frac{5x^2+50x+2x+20+5x^4−50x^3−2x^3+20x^2−100}{(x−10)(x+10)}$ =$\frac{(5x 2 +20x 2 )+(50x+2x)+(20−100)+5x 4 +(−50x 3 −2x 3 )}{(x−10)(x+10)}$ =$\frac{25x^2 +52x−80+5x^4 −52x^3 }{(x−10)(x+10)}$ xin hay nhất! :))) Bình luận
Đáp án:
Giải thích các bước giải:
$\frac{\left( 5x+2 \right)\left( x+10 \right)+\left( 5x-2 \right)\left( x-10 \right).2-100}{\left( x-10 \right)\left( x+10 \right)}$
$=\frac{5{{x}^{2}}+50x+2x+20+\left( 5{{x}^{2}}-50x-2x+20 \right).2-100}{{{x}^{2}}-100}$
$=\frac{5{{x}^{2}}+52x+20+10{{x}^{2}}-100x-4x+40-100}{{{x}^{2}}-100}$
$=\frac{15{{x}^{2}}-52x-40}{{{x}^{2}}-100}$
Giải thích các bước giải:
$\frac{(5x+2)(x+10)+(5x–2)(x–10)x^2−100}{(x-10)(x+10)}$
=$\frac{(5x+2)(x+10)+x^2(5x−2)(x−10)−100}{(x−10)(x+10)}$
=$\frac{5x^2+50x+2x+20+5x^4−50x^3−2x^3+20x^2−100}{(x−10)(x+10)}$
=$\frac{(5x 2 +20x 2 )+(50x+2x)+(20−100)+5x 4 +(−50x 3 −2x 3 )}{(x−10)(x+10)}$
=$\frac{25x^2 +52x−80+5x^4 −52x^3 }{(x−10)(x+10)}$
xin hay nhất! :)))