5-2x-7-x=4-35-41 7-8+(5x-3)=6 2(x-3)+7-x=25 3(x-2)-2(x+1)=41 5(x-1)+6(x-1)=33 05/07/2021 Bởi Gianna 5-2x-7-x=4-35-41 7-8+(5x-3)=6 2(x-3)+7-x=25 3(x-2)-2(x+1)=41 5(x-1)+6(x-1)=33
1. $5-2x-7-x=4-35-41$ $-3x=4-35-41-5+7$ $-3x=-70$ `→ x=\frac{70}{3}` 2. $7-8+(5x-3)=6$ $5x-3=6-7+8$ $5x=6-7+8+3$ $5x=10$ $→x=2$ 3. $2(x-3)+7-x=25$ $2x-6+7-x=25$ $x=25-7+6$ $→ x=24$ 4. $3(x-2)-2(x+1)=41$ $3x-6-2x-2=41$ $x=41+2+6$ $→x=49$ 5. $5(x-1)+6(x-1)=33$ $5x-5+6x-6=33$ $11x=33+5+6$ $11x=44$ $→x=4$ Bình luận
5-2x-7-x=4-35-41 ⇒-3x=4-35-41-5+7 ⇒-3x=-70 ⇒x=70/3 b,7-8+(5x-3)=6 ⇒5x-3=6-7+8 ⇒5x=6-7+8+3 ⇒5x=10 ⇒x=2 c,2(x-3)+7-x=25 ⇒2x-6+7-x=25 ⇒x=25-7+6 ⇒x=24 d,3(x-2)-2(x+1)=41 ⇒3x-6-2x-2=41 ⇒x=41+2+6 ⇒x=49 e,5(x-1)+6(x-1)=33 ⇒5x-5+6x-6=33 ⇒11x=33+5+6 ⇒11x=44 ⇒x=4 Chúc bạn học tốt nhé! ^^ Bình luận
1.
$5-2x-7-x=4-35-41$
$-3x=4-35-41-5+7$
$-3x=-70$
`→ x=\frac{70}{3}`
2.
$7-8+(5x-3)=6$
$5x-3=6-7+8$
$5x=6-7+8+3$
$5x=10$
$→x=2$
3.
$2(x-3)+7-x=25$
$2x-6+7-x=25$
$x=25-7+6$
$→ x=24$
4.
$3(x-2)-2(x+1)=41$
$3x-6-2x-2=41$
$x=41+2+6$
$→x=49$
5.
$5(x-1)+6(x-1)=33$
$5x-5+6x-6=33$
$11x=33+5+6$
$11x=44$
$→x=4$
5-2x-7-x=4-35-41
⇒-3x=4-35-41-5+7
⇒-3x=-70
⇒x=70/3
b,7-8+(5x-3)=6
⇒5x-3=6-7+8
⇒5x=6-7+8+3
⇒5x=10
⇒x=2
c,2(x-3)+7-x=25
⇒2x-6+7-x=25
⇒x=25-7+6
⇒x=24
d,3(x-2)-2(x+1)=41
⇒3x-6-2x-2=41
⇒x=41+2+6
⇒x=49
e,5(x-1)+6(x-1)=33
⇒5x-5+6x-6=33
⇒11x=33+5+6
⇒11x=44
⇒x=4
Chúc bạn học tốt nhé! ^^