(x+5).(x-4)=0 -x(x+1)=0 9.(2x-10)=0 l-xl.lx-2l=0 3.lx-2l+2x

(x+5).(x-4)=0
-x(x+1)=0
9.(2x-10)=0
l-xl.lx-2l=0
3.lx-2l+2x

0 bình luận về “(x+5).(x-4)=0 -x(x+1)=0 9.(2x-10)=0 l-xl.lx-2l=0 3.lx-2l+2x”

  1. `(x+5).(x-4)=0`

    `<=>`\(\left[ \begin{array}{l}x+5=0\\x-4=0\end{array} \right.\)

    `<=>`\(\left[ \begin{array}{l}x=-5\\x=4\end{array} \right.\)

    Vậy `x ∈  {-5,4}`

    `-x(x+1)=0`

    `<=>`\(\left[ \begin{array}{l}-x=0\\x+1=0\end{array} \right.\)

    `<=>`\(\left[ \begin{array}{l}x=0\\x=-1\end{array} \right.\)

    Vậy `x ∈ {0;-1}` 

    `9.(2x-10)=0`

    `<=>18x-90=0`

    `<=>18x=90`

    `<=>x=5`

    Vậy `x ∈ {5}`

    `|-x |.|x-2|=0`

    `<=>`\(\left[ \begin{array}{l}x=0\\x-2=0\end{array} \right.\)

    `<=>`\(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\)

    Vậy `x∈ {0;2}`

    `3.|x-2|+2x = 19`

    `<=>3x-6+2x=19`

    `<=>5x-6=19`

    `<=>5x=25`

    `<=>x=5`

    Vậy `x ∈ {5}`

     

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  2. `a)(x+5).(x-4)=0`

    `→` \(\left[ \begin{array}{l}x+5=0\\x-4=0\end{array} \right.\) 

    `→` \(\left[ \begin{array}{l}x=-5\\x=4\end{array} \right.\) 

    Vậy `x∈{-5;4}`

    `b)-x(x+1)=0`

    `→` \(\left[ \begin{array}{l}-x=0\\x+1=0\end{array} \right.\) 

    `→` \(\left[ \begin{array}{l}x=0\\x=-1\end{array} \right.\) 

    Vậy `x∈{0;-1}`

    `c)9.(2x-10)=0`

    `→2x-10=0`

    `→2x=10`

    `→x=10:2`

    `→x=5`

    Vậy `x=5`

    `d)|-x|.|x-2|=0`

    `→` \(\left[ \begin{array}{l}x=0\\x-2=0\end{array} \right.\) 

    `→` \(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\) 

    Vậy `x∈{0;2}`

    `e)` không có kết quả.

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