(X + 5)(x – 5) -(x-3)(x^2-3x+9)=5-x(x^2-x-2) 04/09/2021 Bởi Nevaeh (X + 5)(x – 5) -(x-3)(x^2-3x+9)=5-x(x^2-x-2)
Đáp án: `(X + 5)(x – 5) -(x-3)(x^2-3x+9)=5-x(x^2-x-2)` Chuyển vế đổi dấu ta được : `⇒(X + 5)(x – 5) -(x-3)(x^2-3x+9)-5+x(x^2-x-2)=0` `⇒6x²-16x-3=0` ⇒\(\left[ \begin{array}{l}x=\frac{8+\sqrt{82}}{6}\\x=\frac{8-\sqrt{82}}{6}\end{array} \right.\) Bình luận
$\text { Đáp án: }$ ` (x + 5)(x – 5) – (x – 3)(x² – 3x + 9) = 5 – x(x² – x – 2) ` ` <=> (x + 5)(x – 5) – (x – 3)(x² – 3x + 9) – 5 + x(x² – x – 2) ` ` <=> 6x² – 16x – 3 = 0 ` ` <=> ` \(\left[ \begin{array}{l}x=\frac{8+\sqrt{82}}{6}\\x=\frac{8-\sqrt{82}}{6}\end{array} \right.\) ` \text { Vậy } S = { \frac{8+\sqrt{82}}{6} ; \frac{8-\sqrt{82}}{6} } ` Bình luận
Đáp án:
`(X + 5)(x – 5) -(x-3)(x^2-3x+9)=5-x(x^2-x-2)`
Chuyển vế đổi dấu ta được :
`⇒(X + 5)(x – 5) -(x-3)(x^2-3x+9)-5+x(x^2-x-2)=0`
`⇒6x²-16x-3=0`
⇒\(\left[ \begin{array}{l}x=\frac{8+\sqrt{82}}{6}\\x=\frac{8-\sqrt{82}}{6}\end{array} \right.\)
$\text { Đáp án: }$
` (x + 5)(x – 5) – (x – 3)(x² – 3x + 9) = 5 – x(x² – x – 2) `
` <=> (x + 5)(x – 5) – (x – 3)(x² – 3x + 9) – 5 + x(x² – x – 2) `
` <=> 6x² – 16x – 3 = 0 `
` <=> ` \(\left[ \begin{array}{l}x=\frac{8+\sqrt{82}}{6}\\x=\frac{8-\sqrt{82}}{6}\end{array} \right.\)
` \text { Vậy } S = { \frac{8+\sqrt{82}}{6} ; \frac{8-\sqrt{82}}{6} } `