5x+6/7_3x+1/4=x+16/5 X+5/4-2x-5/3=6x-1/3+2x-3/6 1-2x-1/9=x/2-13x-10/6 Cảm ơn ạ

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1. Đáp án:

   a) 5x+6/7-3x+1/4=x+16/5

   => x+6/7+1/4-16/5=0

   => x-293/140=0

   => x=293/140

   b) X+5/4-2x-5/3=6x-1/3+2x-3/6

   => -9x +5/4-5/3+1/3+3/6=0

   => -9x+5/12=0

   => -9x=-5/12

   => x= 5/108

   c) 1-2x-1/9=x/2-13x-10/6

   => -2x-x/2+13x=1/9-1-10/6

   => -4x-x+26x=-23/9

   => 21x=-23/9

   => x=-23/189

    

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2. $a) \frac{5x -6}{7} – \frac{3x +1}{4} = \frac{x +16}{5}$

   $⇔ \frac{20(5x -6)}{140} – \frac{35(3x +1)}{140} = \frac{28(x +16)}{140}$

   $⇔ 20(5x -6) – 35(3x +1) = 28(x +16)$

   $⇔ 100x -120 -105x -35 = 28x +448$

   $⇔ -33x = 603$

   $⇔ x = \frac{-201}{11}$

   $Vậy$ $S =$ {$ \frac{201}{11}$}

   $b) \frac{x +5}{4} – \frac{2x -5}{3} = \frac{6x -1}{3} + \frac{2x -3}{6}$

   $⇔ \frac{3(x +5)}{12} – \frac{4(2x -5)}{12} = \frac{4(6x -1)}{12} + \frac{2(2x -3)}{12}$

   $⇔ 3(x +5) – 4(2x -5) = 4(6x -1) + 2(2x -3)$

   $⇔ 3x +15 -8x +20 = 24x -4 +4x -6$

   $⇔ -33x = -45$

   $⇔ x = \frac{15}{11}$

   $Vậy$ $S =$ {$\frac{15}{11}$}

   $c) 1 – \frac{2x -1}{9} = \frac{x}{2} – \frac{13x -10}{6}$

   $⇔ \frac{18}{18} – \frac{2(2x -1)}{18} = \frac{9x}{18} – \frac{3(13x -10)}{18}$

   $⇔ 18 -2(2x -1) = 9x -3(13x -10)$

   $⇔ 18 -4x +2 = 9x -39x +30$

   $⇔ 26x = 10$

   $⇔ x = \frac{5}{13}$

   $Vậy$ $S =$ {$\frac{5}{13}$}

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