x+5 chia hết cho x+1 x+3 chia hết cho x-1 x-10 chia hết x-5 7 chia hết x+1 -5 chia hết x-1 9 chia hết cho x+2 29/10/2021 Bởi Ruby x+5 chia hết cho x+1 x+3 chia hết cho x-1 x-10 chia hết x-5 7 chia hết x+1 -5 chia hết x-1 9 chia hết cho x+2
Đáp án: 6) \(\left[ \begin{array}{l}x = 7\\x = – 11\\x = 1\\x = – 5\\x = – 1\\x = – 3\end{array} \right.\) Giải thích các bước giải: \(\begin{array}{l}1)x + 5 \vdots x + 1\\ \to x + 1 + 4 \vdots x + 1\\ \to 4 \vdots x + 1\\ \to x + 1 \in U\left( 4 \right)\\ \to \left[ \begin{array}{l}x + 1 = 4\\x + 1 = – 4\\x + 1 = 2\\x + 1 = – 2\\x + 1 = 1\\x + 1 = – 1\end{array} \right. \to \left[ \begin{array}{l}x = 3\\x = – 5\\x = 1\\x = – 3\\x = 0\\x = – 2\end{array} \right.\\2)x + 3 \vdots x – 1\\ \to x – 1 + 4 \vdots x – 1\\ \to 4 \vdots x – 1\\ \to x – 1 \in U\left( 4 \right)\\ \to \left[ \begin{array}{l}x – 1 = 4\\x – 1 = – 4\\x – 1 = 2\\x – 1 = – 2\\x – 1 = 1\\x – 1 = – 1\end{array} \right. \to \left[ \begin{array}{l}x = 5\\x = – 3\\x = 3\\x = – 1\\x = 2\\x = 0\end{array} \right.\\3)x – 10 \vdots x – 5\\ \to x – 5 – 5 \vdots x – 5\\ \to 5 \vdots x – 5\\ \to x – 5 \in U\left( 5 \right)\\ \to \left[ \begin{array}{l}x – 5 = 5\\x – 5 = – 5\\x – 5 = 1\\x – 5 = – 1\end{array} \right. \to \left[ \begin{array}{l}x = 10\\x = 0\\x = 6\\x = 4\end{array} \right.\\4)7 \vdots x + 1\\ \to x + 1 \in U\left( 7 \right)\\ \to \left[ \begin{array}{l}x + 1 = 7\\x + 1 = – 7\\x + 1 = 1\\x + 1 = – 1\end{array} \right. \to \left[ \begin{array}{l}x = 6\\x = – 8\\x = 0\\x = – 2\end{array} \right.\\5) – 5 \vdots x – 1\\ \to 5 \vdots x – 1\\ \to x – 1 \in U\left( 5 \right)\\ \to \left[ \begin{array}{l}x – 1 = 5\\x – 1 = – 5\\x – 1 = 1\\x – 1 = – 1\end{array} \right. \to \left[ \begin{array}{l}x = 6\\x = – 4\\x = 2\\x = 0\end{array} \right.\\6)9 \vdots x + 2\\ \to x + 2 \in U\left( 9 \right)\\ \to \left[ \begin{array}{l}x + 2 = 9\\x + 2 = – 9\\x + 2 = 3\\x + 2 = – 3\\x + 2 = 1\\x + 2 = – 1\end{array} \right. \to \left[ \begin{array}{l}x = 7\\x = – 11\\x = 1\\x = – 5\\x = – 1\\x = – 3\end{array} \right.\end{array}\) Bình luận
Đáp án:
6) \(\left[ \begin{array}{l}
x = 7\\
x = – 11\\
x = 1\\
x = – 5\\
x = – 1\\
x = – 3
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
1)x + 5 \vdots x + 1\\
\to x + 1 + 4 \vdots x + 1\\
\to 4 \vdots x + 1\\
\to x + 1 \in U\left( 4 \right)\\
\to \left[ \begin{array}{l}
x + 1 = 4\\
x + 1 = – 4\\
x + 1 = 2\\
x + 1 = – 2\\
x + 1 = 1\\
x + 1 = – 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 3\\
x = – 5\\
x = 1\\
x = – 3\\
x = 0\\
x = – 2
\end{array} \right.\\
2)x + 3 \vdots x – 1\\
\to x – 1 + 4 \vdots x – 1\\
\to 4 \vdots x – 1\\
\to x – 1 \in U\left( 4 \right)\\
\to \left[ \begin{array}{l}
x – 1 = 4\\
x – 1 = – 4\\
x – 1 = 2\\
x – 1 = – 2\\
x – 1 = 1\\
x – 1 = – 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 5\\
x = – 3\\
x = 3\\
x = – 1\\
x = 2\\
x = 0
\end{array} \right.\\
3)x – 10 \vdots x – 5\\
\to x – 5 – 5 \vdots x – 5\\
\to 5 \vdots x – 5\\
\to x – 5 \in U\left( 5 \right)\\
\to \left[ \begin{array}{l}
x – 5 = 5\\
x – 5 = – 5\\
x – 5 = 1\\
x – 5 = – 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 10\\
x = 0\\
x = 6\\
x = 4
\end{array} \right.\\
4)7 \vdots x + 1\\
\to x + 1 \in U\left( 7 \right)\\
\to \left[ \begin{array}{l}
x + 1 = 7\\
x + 1 = – 7\\
x + 1 = 1\\
x + 1 = – 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 6\\
x = – 8\\
x = 0\\
x = – 2
\end{array} \right.\\
5) – 5 \vdots x – 1\\
\to 5 \vdots x – 1\\
\to x – 1 \in U\left( 5 \right)\\
\to \left[ \begin{array}{l}
x – 1 = 5\\
x – 1 = – 5\\
x – 1 = 1\\
x – 1 = – 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 6\\
x = – 4\\
x = 2\\
x = 0
\end{array} \right.\\
6)9 \vdots x + 2\\
\to x + 2 \in U\left( 9 \right)\\
\to \left[ \begin{array}{l}
x + 2 = 9\\
x + 2 = – 9\\
x + 2 = 3\\
x + 2 = – 3\\
x + 2 = 1\\
x + 2 = – 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 7\\
x = – 11\\
x = 1\\
x = – 5\\
x = – 1\\
x = – 3
\end{array} \right.
\end{array}\)
Đây nhé