7² . 5 – ( 2 . |x| + 3^0 ) = 630 : 3^2 . 1^10

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1. Tìm `x` ?

   `7^2 . 5 – (2.|x|+3^0)=630 : 3^2 . 1^10`

   `=>49 . 5 – (2 .|x| + 1 ) = 630 : 9 . 1`

   `=>245 – 2|x|-1=70`

   `=>2|x|=174`

   `=>|x|=87`

   `=>x=±87`

    

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2. `\text{~~Holi~~}`

   `7^2 . 5-(2|x|+3^0)=630:3^2 . 1^{10}`

   `-> 245-2|x|-1=630/3^2`

   `-> 244-2|x|=70`

   `-> -2|x|=174`

   `-> |x|=87`

   `->` \(\left[ \begin{array}{l}x=87\\x=-87\end{array} \right.\)

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