7$\frac{1}{3}$.($\frac{1}{6}$-$\frac{1}{2}$) ≤ x ≤ $\frac{3}{4}$.($\frac{1}{6}$-$\frac{1}{5}$-$\frac{1}{15}$)

7$\frac{1}{3}$.($\frac{1}{6}$-$\frac{1}{2}$) ≤ x ≤ $\frac{3}{4}$.($\frac{1}{6}$-$\frac{1}{5}$-$\frac{1}{15}$)

0 bình luận về “7$\frac{1}{3}$.($\frac{1}{6}$-$\frac{1}{2}$) ≤ x ≤ $\frac{3}{4}$.($\frac{1}{6}$-$\frac{1}{5}$-$\frac{1}{15}$)”

  1. Đáp án:

    `7 1/3 (1/6 – 1/2) ≤ x ≤ 3/4 (1/6 – 1/5 – 1/15)`

    `⇔ 22/3 . (-1)/3 ≤ x ≤ 3/4 . (-1)/10`

    `⇔ (-22)/9 ≤ x ≤ (-3)/40`

    `text{Vậy :}` `(-22)/9 ≤ x ≤ (-3)/40`

     

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  2. $7$$\frac{1}{3}$.($\frac{1}{6}$-$\frac{1}{2}$)≤$x$≤$\frac{3}{4}$.( $\frac{1}{6}$-$\frac{1}{5}$-$\frac{1}{15}$)  

    $\frac{22}{3}$.($\frac{1}{6}$-$\frac{3}{6}$)≤$x$≤$\frac{3}{4}$.( $\frac{5}{30}$-$\frac{6}{30}$-$\frac{2}{30}$) 

    $\frac{22}{3}$.$\frac{-1}{3}$≤$x$≤$\frac{3}{4}$.$\frac{-1}{10}$

    $\frac{-22}{9}$≤$x$≤$\frac{-3}{40}$.

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