$(8-x)(x-19)=0 $ ⇒\(\left[ \begin{array}{l}8-x\\x-19=0\end{array} \right.\) ⇒\(\left[ \begin{array}{l}x=8\\x=19\end{array} \right.\) $\text{Vậy x=8 hoặc x= 19}$ Bình luận
( 8 – x ) ( x – 19 ) = 0 ⇒ \(\left[ \begin{array}{l}8-x=0\\x-19=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=8\\x=19\end{array} \right.\) Vậy x ∈ { 8 ; 19 } Bình luận
$(8-x)(x-19)=0 $
⇒\(\left[ \begin{array}{l}8-x\\x-19=0\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=8\\x=19\end{array} \right.\)
$\text{Vậy x=8 hoặc x= 19}$
( 8 – x ) ( x – 19 ) = 0
⇒ \(\left[ \begin{array}{l}8-x=0\\x-19=0\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=8\\x=19\end{array} \right.\)
Vậy x ∈ { 8 ; 19 }