80-(4.5 mũ 2-3.2 mũ 3)
1997-[10.(4 mũ 3-56):2 mũ 3 +2 mũ3].2005
35-{12-[-14+(-2)]}
49-(-54)-23
13-18-(-42)-15
-452-(-67+75-452)
5+(-7)+9+(-11)+13+(-15)
-(-23)+(-36)+|57|-(-29)-35
2 mũ 2.3-(1 mũ 2000+8):3 mũ 2
5002.18+99.18-(3 mũ 3.3 mũ2+2 mũ4.2
Giải giúp ạ
80-(4.5 mũ 2-3.2 mũ 3) 1997-[10.(4 mũ 3-56):2 mũ 3 +2 mũ3].2005 35-{12-[-14+(-2)]} 49-(-54)-23 13-18-(-42)-15 -452-(-67+75-452) 5+(-7)+9+(-11)+13+(-15
By Adeline
\(\begin{array}{l}80 – \left( {{{4.5}^2} – {{3.2}^3}} \right)\\ = 80 – \left( {4.25 – 3.8} \right)\\ = 80 – \left( {100 – 24} \right)\\ = 80 – 100 + 24\\ = \,\,\, – 20 + 24\\ = \,\,\,\,\,\,\,\,\,\,4\end{array}\)
\(\begin{array}{l}1997 – \left[ {10.\left( {{4^3} – 56} \right):{2^3} + {2^3}} \right].2005\\ = 1997 – \left[ {10.\left( {64 – 56} \right):8 + 8} \right].2005\\ = 1997 – \left[ {10.8:8 + 8} \right].2005\\ = 1997 – \,\,\,\,\,\,18.2005\\ = 1997 – 36090\\ = – 34093\end{array}\)
\(\begin{array}{l}35 – \left\{ {12 – \left[ { – 14 + \left( { – 2} \right)} \right]} \right\}\\ = 35 – \left( {12 + 16} \right)\\ = 35 – \,\,\,\,28\\ = 7\end{array}\)
\(\begin{array}{l}49 – \left( { – 54} \right) – 23\\ = 49 + 54 – 23\\ = 49 + 31\\ = 80\end{array}\)
Đáp án:
1/ 4
2/ -34093
3/ 7
4/ 80
5/ 22
6/ -8
7/ -6
8/ -8
9/ 11
10/ 91543
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