8a+12b 3x(x-3)+2(x-3) m^2-mx-5m+5x 9x^2-12xy+4 x^2+2xy+x+2y 08/09/2021 Bởi Peyton 8a+12b 3x(x-3)+2(x-3) m^2-mx-5m+5x 9x^2-12xy+4 x^2+2xy+x+2y
Em xem lại đề bài ý thứ 4 nhé \(\begin{array}{l} 8a + 12b = 4\left( {2a + 3b} \right)\\ 3x\left( {x – 3} \right) + 2\left( {x – 3} \right) = \left( {x – 3} \right)\left( {3x + 2} \right)\\ {m^2} – mx – 5m + 5x = m\left( {m – x} \right) – 5\left( {m – x} \right) = \left( {m – x} \right)\left( {m – 5} \right)\\ 9{x^2} – 12xy + 4{y^2} = {\left( {3x} \right)^2} – 2.3x.2y + {\left( {2y} \right)^2} = {\left( {3x – 2y} \right)^2}\\ {x^2} + 2xy + x + 2y = x\left( {x + 2y} \right) + \left( {x + 2y} \right) = \left( {x + 2y} \right)\left( {x + 1} \right) \end{array}\) Bình luận
Em xem lại đề bài ý thứ 4 nhé
\(\begin{array}{l}
8a + 12b = 4\left( {2a + 3b} \right)\\
3x\left( {x – 3} \right) + 2\left( {x – 3} \right) = \left( {x – 3} \right)\left( {3x + 2} \right)\\
{m^2} – mx – 5m + 5x = m\left( {m – x} \right) – 5\left( {m – x} \right) = \left( {m – x} \right)\left( {m – 5} \right)\\
9{x^2} – 12xy + 4{y^2} = {\left( {3x} \right)^2} – 2.3x.2y + {\left( {2y} \right)^2} = {\left( {3x – 2y} \right)^2}\\
{x^2} + 2xy + x + 2y = x\left( {x + 2y} \right) + \left( {x + 2y} \right) = \left( {x + 2y} \right)\left( {x + 1} \right)
\end{array}\)