A) 0,5x – $\frac{2}{3}$x = $\frac{5}{6}$ B) $\frac{3}{x+60}$ = 60% C) $\frac{1}{5}$ x + $\frac{4}{5}$ x = $\frac{(-3mũ2)}{2}$ D) $\frac{x}{3

Bởi

A) 0,5x – $\frac{2}{3}$x = $\frac{5}{6}$
B) $\frac{3}{x+60}$ = 60%
C) $\frac{1}{5}$ x + $\frac{4}{5}$ x = $\frac{(-3mũ2)}{2}$
D) $\frac{x}{3}$ – $\frac{x}{4}$ = -1 $\frac{5}{12}$

0 bình luận về “A) 0,5x – $\frac{2}{3}$x = $\frac{5}{6}$ B) $\frac{3}{x+60}$ = 60% C) $\frac{1}{5}$ x + $\frac{4}{5}$ x = $\frac{(-3mũ2)}{2}$ D) $\frac{x}{3”

  2. $a$) `0,5x – 2/3x = 5/6`

    `⇔ x (1/2 – 2/3) = 5/6`

    `⇔ x . -1/6 = 5/6`

    `⇔ x = -5`

      Vậy $x=-5$

    $b$) `{3}/{x+60} = 60\%`

    `⇔ 3/{x+60} = {60}/100`

    `⇔ 3/{x+60} = 3/5`

    `⇔ x + 60 = 5`

    `⇔ x = -55`

       Vậy `x=-55`

    $c$) `1/5 .x + 4/5 . x = {(-3)^2}/{2}`

    `⇔ x . (1/5 + 4/5) = 9/2`

    `⇔ x . 1 = 9/2`

    `⇔ x = 9/2`

       Vậy `x=9/2`

    $d$) `x/3 – x/4 = -1 5/12`

    `⇔ {4x-3x}/12 = – 17/12`

    `⇔ x = -17`

      Vậy `x=-17`

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