A=(1-1/2)(1-1/3)(1-1/4)….(1-1/2019)(1-1/2020) giúp mik lm nha 02/10/2021 Bởi Everleigh A=(1-1/2)(1-1/3)(1-1/4)….(1-1/2019)(1-1/2020) giúp mik lm nha
$A= (1 – 1/2).(1-1/3).(1-1/4)….(1-1/2019).(1-1/2020)$ $⇔ A = 1/2 . 2/3 . 3/4 ….2018/2019.2019/2020$ $⇔ A = 1.2.3.4…..2018.2019/2.3.4…..2019.2020$ $⇔ A = 1/2020$ Bình luận
`A=(1-1/2)(1-1/3)(1-1/4)…(1-1/2019)(1-1/2020)` `⇒A=1/2 . 2/3 . 3/4…2018/2019 . 2019/2020` `⇒A={1.2.3…2018.2019}/{2.3.4…2019.2020}` `⇒A=1/2020` Bình luận
$A= (1 – 1/2).(1-1/3).(1-1/4)….(1-1/2019).(1-1/2020)$
$⇔ A = 1/2 . 2/3 . 3/4 ….2018/2019.2019/2020$
$⇔ A = 1.2.3.4…..2018.2019/2.3.4…..2019.2020$
$⇔ A = 1/2020$
`A=(1-1/2)(1-1/3)(1-1/4)…(1-1/2019)(1-1/2020)`
`⇒A=1/2 . 2/3 . 3/4…2018/2019 . 2019/2020`
`⇒A={1.2.3…2018.2019}/{2.3.4…2019.2020}`
`⇒A=1/2020`