A= 1/1×2+1/3×4+…+1/199×200 B=1/101+1/102+…+1/200 Tính A/B 10/08/2021 Bởi Iris A= 1/1×2+1/3×4+…+1/199×200 B=1/101+1/102+…+1/200 Tính A/B
A=1/1×2+1/3×4+…+1/199×200. A=1-1/2+1/2-1/3+1/3-1/4+…+1/99-1/100 A=1-1/100 A=99/100 B=1/101+1/102+…+1/200 B=(1/101+1/102+…+1/120)+(1/121+1/122+..+1/150)+(1/151+1/180)+(1/181+…+1/200) B=20.1/120+30.1/150+30.1/180+20,1/200 B=99/100 Vậy A/B= 99/100 phần 99/100 A/B=1 cho mk ctlhn nha!!!!!!!! chúc bạn học tốt!!!!!!!!! Bình luận
A = $\frac{1}{1.2}$ + $\frac{1}{3.4}$ + …. + $\frac{1}{199.200}$ = 1 – $\frac{1}{2}$ + $\frac{1}{3}$ – $\frac{1}{4}$ + …. + $\frac{1}{199}$ – $\frac{1}{200}$ = (1 + $\frac{1}{2}$ + $\frac{1}{3}$ + $\frac{1}{4}$ + …. + $\frac{1}{199}$ + $\frac{1}{200}$) – 2($\frac{1}{2}$ + $\frac{1}{4}$ + …. + $\frac{1}{200}$) = (1 + $\frac{1}{2}$ + $\frac{1}{3}$ + $\frac{1}{4}$ + …. + $\frac{1}{199}$ + $\frac{1}{200}$) – (1 + $\frac{1}{2}$ + …. + $\frac{1}{100}$ = $\frac{1}{101}$ + $\frac{1}{102}$ + …. + $\frac{1}{200}$ B = $\frac{1}{101}$ + $\frac{1}{102}$ + …. + $\frac{1}{200}$ ⇒ $\frac{A}{B}$ = $\frac{\frac{1}{101} + \frac{1}{102} + …. + \frac{1}{200}}{\frac{1}{101} + \frac{1}{102} + …. + \frac{1}{200}}$ = 1 Bình luận
A=1/1×2+1/3×4+…+1/199×200.
A=1-1/2+1/2-1/3+1/3-1/4+…+1/99-1/100
A=1-1/100
A=99/100
B=1/101+1/102+…+1/200
B=(1/101+1/102+…+1/120)+(1/121+1/122+..+1/150)+(1/151+1/180)+(1/181+…+1/200)
B=20.1/120+30.1/150+30.1/180+20,1/200
B=99/100
Vậy A/B=
99/100 phần 99/100
A/B=1
cho mk ctlhn nha!!!!!!!!
chúc bạn học tốt!!!!!!!!!
A = $\frac{1}{1.2}$ + $\frac{1}{3.4}$ + …. + $\frac{1}{199.200}$
= 1 – $\frac{1}{2}$ + $\frac{1}{3}$ – $\frac{1}{4}$ + …. + $\frac{1}{199}$ – $\frac{1}{200}$
= (1 + $\frac{1}{2}$ + $\frac{1}{3}$ + $\frac{1}{4}$ + …. + $\frac{1}{199}$ + $\frac{1}{200}$) – 2($\frac{1}{2}$ + $\frac{1}{4}$ + …. + $\frac{1}{200}$)
= (1 + $\frac{1}{2}$ + $\frac{1}{3}$ + $\frac{1}{4}$ + …. + $\frac{1}{199}$ + $\frac{1}{200}$) – (1 + $\frac{1}{2}$ + …. + $\frac{1}{100}$
= $\frac{1}{101}$ + $\frac{1}{102}$ + …. + $\frac{1}{200}$
B = $\frac{1}{101}$ + $\frac{1}{102}$ + …. + $\frac{1}{200}$
⇒ $\frac{A}{B}$ = $\frac{\frac{1}{101} + \frac{1}{102} + …. + \frac{1}{200}}{\frac{1}{101} + \frac{1}{102} + …. + \frac{1}{200}}$ = 1