a)|x+1/2| – 4/5 = 0 b) |x-1,2|.5 = 0 c) |1/2 – x|-1/2 =0 d) |3 – x| . 7 = 0

`a)`

`|x+1/2| – 4/5 = 0`

` | x + 1/2 |  – 4/5 = 0`

`| x + 1/2| = 0 + 4/5`

`| x  + 1/2|  = 4/5`

\(\left[ \begin{array}{l}x+\frac{1}{2} = \frac{4}{5} \\x+\frac{1}{2} = \frac{-4}{5}\end{array} \right.\)

\(\left[ \begin{array}{l}x=3\\x=\frac{-13}{14}\end{array} \right.\)

`b)`

`|x-1,2|.5 = 0`

`x- 1,2 . 5 = 0`

`x=  0: 5  +1,2`

`x = 1,2`

`c)`

`|1/2 – x|-1/2 =0`

`|x – 1/2| = 1/2 – 0`

`|x – 1/2 | = 1/2`

\(\left[ \begin{array}{l}x -\frac{1}{2 } =\frac{1}{2}\\x -\frac{1}{2 } =\frac{-1}{2}\end{array} \right.\)

\(\left[ \begin{array}{l}x=1\\x=0\end{array} \right.\)

`d)`

`|3 – x| . 7 = 0`

`|3 -x| = 0 :7`

`|3 – x| = 0`

`3 – x =0`

`x = 3 -0`

`x = 3`