A=1/2 mũ 2 + 1/2 mũ 4 + 1/2 mũ 8 +….+1/2 mũ 100 chứng minh A nhỏ hơn 1/3 05/09/2021 Bởi Arya A=1/2 mũ 2 + 1/2 mũ 4 + 1/2 mũ 8 +….+1/2 mũ 100 chứng minh A nhỏ hơn 1/3
\(\begin{array}{l}A = \frac{1}{{{2^2}}} + \frac{1}{{{2^4}}} + \frac{1}{{{2^8}}} + … + \frac{1}{{{2^{100}}}}\\{2^2}A = 1 + \frac{1}{{{2^4}}} + \frac{1}{{{2^8}}} + … + \frac{1}{{{2^{50}}}}\\ \Rightarrow 4A – A = 1 – \frac{1}{{{2^{100}}}}\\ \Rightarrow 3A = 1 – \frac{1}{{{2^{100}}}}\\ \Rightarrow A = \frac{1}{3} – \frac{1}{{{{3.2}^{100}}}}\\ \Rightarrow A < \frac{1}{3}\end{array}\) Bình luận
\(\begin{array}{l}
A = \frac{1}{{{2^2}}} + \frac{1}{{{2^4}}} + \frac{1}{{{2^8}}} + … + \frac{1}{{{2^{100}}}}\\
{2^2}A = 1 + \frac{1}{{{2^4}}} + \frac{1}{{{2^8}}} + … + \frac{1}{{{2^{50}}}}\\
\Rightarrow 4A – A = 1 – \frac{1}{{{2^{100}}}}\\
\Rightarrow 3A = 1 – \frac{1}{{{2^{100}}}}\\
\Rightarrow A = \frac{1}{3} – \frac{1}{{{{3.2}^{100}}}}\\
\Rightarrow A < \frac{1}{3}
\end{array}\)