a, 1/4x+5/9=1/3 b, 3/4-(x-2/5)=11/12 c, /x+1/3/+1=4 d,27^x=3^x+2 30/10/2021 Bởi Arianna a, 1/4x+5/9=1/3 b, 3/4-(x-2/5)=11/12 c, /x+1/3/+1=4 d,27^x=3^x+2
Đáp án + Giải thích các bước giải: Ta có : `a,\frac{1}{4}x+\frac{5}{9}=\frac{1}{3}` `→\frac{1}{4}x=-\frac{2}{9}` `→x=-\frac{8}{9}` `b,\frac{3}{4}-(x-\frac{2}{5})=\frac{11}{12}` `→x-\frac{2}{5}=-\frac{1}{6}` `→x=\frac{7}{30}` `c,|x+\frac{1}{3}|+1=4` `→|x+\frac{1}{3}|=3` `→` \(\left[ \begin{array}{l}x+\frac{1}{3}=3\\x+\frac{1}{3}=-3\end{array} \right.\) `→` \(\left[ \begin{array}{l}x=\frac{8}{3}\\x=-\frac{10}{3}\end{array} \right.\) Vậy `x∈{\frac{8}{3};-\frac{10}{3}}` `d,27^x=3^{x+2}` `→(3^3)^x=3^{x+2}` `→3^{3x}=3^{x+2}` `→3x=x+2` `→3x-x=2` `→2x=2` `→x=1` Bình luận
Đáp án: Giải thích các bước giải: `a) 1/4x+5/9=1/3` `=> 1/4x=1/3-5/9` `=> 1/4x=-2/9` `=> x=(-2/9):1/4` `=> x=-8/9` `b) 3/4-(x-2/5)=11/2` `=> x-2/5=3/4-11/2` `=> x-2/5=-1/6` `=> x=(-1/6)+2/5` `=> x=7/30` `c) |x+1/3|+1=4` `=> |x+1/3|=3` `=>` \(\left[ \begin{array}{l}x+\dfrac{1}{3}=3\\x+\dfrac{1}{3}=-3\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=\dfrac{8}{3}\\x=-\dfrac{10}{3}\end{array} \right.\) `d) 27^x=3^(x+2)` `=> 3^(3x)=3^(x+2)` `=> 3x=x+2` `=> 3x-x=2` `=> 2x=2` `=> x=1` Bình luận
Đáp án + Giải thích các bước giải:
Ta có :
`a,\frac{1}{4}x+\frac{5}{9}=\frac{1}{3}`
`→\frac{1}{4}x=-\frac{2}{9}`
`→x=-\frac{8}{9}`
`b,\frac{3}{4}-(x-\frac{2}{5})=\frac{11}{12}`
`→x-\frac{2}{5}=-\frac{1}{6}`
`→x=\frac{7}{30}`
`c,|x+\frac{1}{3}|+1=4`
`→|x+\frac{1}{3}|=3`
`→` \(\left[ \begin{array}{l}x+\frac{1}{3}=3\\x+\frac{1}{3}=-3\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=\frac{8}{3}\\x=-\frac{10}{3}\end{array} \right.\)
Vậy `x∈{\frac{8}{3};-\frac{10}{3}}`
`d,27^x=3^{x+2}`
`→(3^3)^x=3^{x+2}`
`→3^{3x}=3^{x+2}`
`→3x=x+2`
`→3x-x=2`
`→2x=2`
`→x=1`
Đáp án:
Giải thích các bước giải:
`a) 1/4x+5/9=1/3`
`=> 1/4x=1/3-5/9`
`=> 1/4x=-2/9`
`=> x=(-2/9):1/4`
`=> x=-8/9`
`b) 3/4-(x-2/5)=11/2`
`=> x-2/5=3/4-11/2`
`=> x-2/5=-1/6`
`=> x=(-1/6)+2/5`
`=> x=7/30`
`c) |x+1/3|+1=4`
`=> |x+1/3|=3`
`=>` \(\left[ \begin{array}{l}x+\dfrac{1}{3}=3\\x+\dfrac{1}{3}=-3\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=\dfrac{8}{3}\\x=-\dfrac{10}{3}\end{array} \right.\)
`d) 27^x=3^(x+2)`
`=> 3^(3x)=3^(x+2)`
`=> 3x=x+2`
`=> 3x-x=2`
`=> 2x=2`
`=> x=1`