a)|x-1|=4 b)|x+3|=0 c)|x+4|=5-(-1) d)|2×x+3|=5

0 bình luận về “a)|x-1|=4 b)|x+3|=0 c)|x+4|=5-(-1) d)|2×x+3|=5”

1. a) |x-1|=4

   => \(\left[ \begin{array}{l}x-1=4\\x-1=-4\end{array} \right.\) 

   => \(\left[ \begin{array}{l}x=5\\x=-3\end{array} \right.\) 

   b) |x+3|=0

   => x+3=0

   => x=-3

   c. |x+4|=5-(-1)

   => |x+4|=6

   => \(\left[ \begin{array}{l}x+4=6\\x+4=-6\end{array} \right.\) 

   => \(\left[ \begin{array}{l}x=2\\x=-10\end{array} \right.\) 

   d) |2×x+3|=5

   => \(\left[ \begin{array}{l}2x+3=5\\2x+3=-5\end{array} \right.\) 

   => \(\left[ \begin{array}{l}x=1\\x=-4\end{array} \right.\) 

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2. a)|x-1|=4

   ⇒\(\left[ \begin{array}{l}x-1=4\\x-1=-4\end{array} \right.\) =>\(\left[ \begin{array}{l}x=5\\x=-3\end{array} \right.\) 

   Vậy x=5 hoặc x=-3

   b)|x+3|=0

   ⇒x+3=0

   ⇒x=-3

   c)|x+4|=5-(-1)

   ⇒|x+4|=6

   ⇒\(\left[ \begin{array}{l}x+4=6\\x+4=-6\end{array} \right.\) =>\(\left[ \begin{array}{l}x=2\\x=-10\end{array} \right.\) 

   Vậy x=2 hoặc x=-10

   d)|2x+3|=5

   ⇒\(\left[ \begin{array}{l}2x+3=5\\2x+3=-5\end{array} \right.\)=> \(\left[ \begin{array}{l}2x=2\\2x=-8\end{array} \right.\) =>\(\left[ \begin{array}{l}x=1\\x=-4\end{array} \right.\) 

   Vậy x=1 hoặc x=-4

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