a) 11/12 – (2/5 +x) =2/3 b) -x-3/4 = -8/11 01/08/2021 Bởi Skylar a) 11/12 – (2/5 +x) =2/3 b) -x-3/4 = -8/11
a) 11/12 – (2/5 +x) =2/3 => 2/5+x = 11/12 – 2/3 =1/4 => x= -3/20 b)-x-3/4 = -8/11 => -x= -8/11+3/4=1/44 => x= -1/44 Bình luận
Đáp án: $a) \dfrac{11}{12} – (\dfrac{2}{5} +x) = \dfrac{2}{3}$ $⇔ \dfrac{2}{5} – x = \dfrac{11}{12} – \dfrac{2}{3}$ $⇔\dfrac{2}{5} – x = \dfrac{1}{4}$ $⇔ x = \dfrac{2}{5} – \dfrac{1}{4}$ $⇔ x = \dfrac{3}{20}$ Vậy $x=\dfrac{3}{20}$ $b) -x -\dfrac{3}{4} = -\dfrac{8}{11}$ $⇔ – x = -\dfrac{8}{11} + \dfrac{3}{4}$ $⇔ -x = \dfrac{1}{44}$ $⇔ x= -\dfrac{1}{44}$ Vậy $x=-\dfrac{1}{44}$ Bình luận
a) 11/12 – (2/5 +x) =2/3
=> 2/5+x = 11/12 – 2/3 =1/4
=> x= -3/20
b)-x-3/4 = -8/11
=> -x= -8/11+3/4=1/44
=> x= -1/44
Đáp án:
$a) \dfrac{11}{12} – (\dfrac{2}{5} +x) = \dfrac{2}{3}$
$⇔ \dfrac{2}{5} – x = \dfrac{11}{12} – \dfrac{2}{3}$
$⇔\dfrac{2}{5} – x = \dfrac{1}{4}$
$⇔ x = \dfrac{2}{5} – \dfrac{1}{4}$
$⇔ x = \dfrac{3}{20}$
Vậy $x=\dfrac{3}{20}$
$b) -x -\dfrac{3}{4} = -\dfrac{8}{11}$
$⇔ – x = -\dfrac{8}{11} + \dfrac{3}{4}$
$⇔ -x = \dfrac{1}{44}$
$⇔ x= -\dfrac{1}{44}$
Vậy $x=-\dfrac{1}{44}$