A) 12.x – 27 : 24 = 28 D ) 130 – [ 5. (9- x) + 43 ] = 47 F) ( 5 ^2 = 3^2) . x + ( 5^ 2 – 3^2 ) .x -40 .x= 10^ 2

A) 12.x – 27 : 24 = 28
D ) 130 – [ 5. (9- x) + 43 ] = 47
F) ( 5 ^2 = 3^2) . x + ( 5^ 2 – 3^2 ) .x -40 .x= 10^ 2

0 bình luận về “A) 12.x – 27 : 24 = 28 D ) 130 – [ 5. (9- x) + 43 ] = 47 F) ( 5 ^2 = 3^2) . x + ( 5^ 2 – 3^2 ) .x -40 .x= 10^ 2”

  1. `a) => 12x-27=28.24=672`

    `=> 12x=672+26=976`

    `=> x=976:12=244/3`

    `b) => 130-[45-5x+43]=47`

    `=> 130-[88-5x]=47`

    `=> 88-5x=130-47=83`

    `=> 5x=88-83=5`

    `=> x=5:5=1`

    `c) => 16.x+16.x-40x=100`

    `=> -8x=100`

    `=> x=-12,5`

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