a 1phần4 -(x+1phần2)=3phần5 bà|x-1,4|=2,6 20/11/2021 Bởi Elliana a 1phần4 -(x+1phần2)=3phần5 bà|x-1,4|=2,6
$\text{a) $\dfrac{1}{4}$ – (x + $\dfrac{1}{2}$) = $\dfrac{3}{5}$}$ $\text{x + $\dfrac{1}{2}$ = $\dfrac{1}{4}$ – $\dfrac{3}{5}$}$ $\text{x + $\dfrac{1}{2}$ = $\dfrac{1}{4}$ – $\dfrac{3}{5}$}$ $\text{x + $\dfrac{1}{2}$ = $\dfrac{5}{20}$ – $\dfrac{12}{20}$}$ $\text{x + $\dfrac{1}{2}$ = $\dfrac{-7}{20}$ }$ $\text{x = $\dfrac{-7}{20}$ – $\dfrac{1}{2}$ }$ $\text{x = $\dfrac{-7}{20}$ – $\dfrac{10}{20}$ }$ $\text{x = $\dfrac{-17}{20}$ }$ $\text{b) |x – 1,4| = 2,6}$ $\text{x – 1,4 = 2,6 hoặc x – 1,4 = -2,6}$ $\text{TH1: x – 1,4 = 2,6}$ $\text{ x = 2,6 + 1,4}$ $\text{ x = 4}$ $\text{TH2: x – 1,4 = -2,6}$ $\text{ x = -2,6 + 1,4}$ $\text{ x = -1,2}$ $\text{Vậy x ∈ {4; -1,2}}$ Bình luận
`a)1/4-(x+1/2)=3/5` `→x+1/2=1/4-3/5` `→x+1/2=-7/20` `→x=-7/20-1/2` `→x=-17/20` Vậy `x=-17/20` `b)|x-1,4|=2,6` `→` \(\left[ \begin{array}{l}x-1,4=2,6\\x-1,4=-2,6\end{array} \right.\) `→` \(\left[ \begin{array}{l}x=4\\x=-1,2\end{array} \right.\) Vậy `x∈{4;-1,2}` Bình luận
$\text{a) $\dfrac{1}{4}$ – (x + $\dfrac{1}{2}$) = $\dfrac{3}{5}$}$
$\text{x + $\dfrac{1}{2}$ = $\dfrac{1}{4}$ – $\dfrac{3}{5}$}$
$\text{x + $\dfrac{1}{2}$ = $\dfrac{1}{4}$ – $\dfrac{3}{5}$}$
$\text{x + $\dfrac{1}{2}$ = $\dfrac{5}{20}$ – $\dfrac{12}{20}$}$
$\text{x + $\dfrac{1}{2}$ = $\dfrac{-7}{20}$ }$
$\text{x = $\dfrac{-7}{20}$ – $\dfrac{1}{2}$ }$
$\text{x = $\dfrac{-7}{20}$ – $\dfrac{10}{20}$ }$
$\text{x = $\dfrac{-17}{20}$ }$
$\text{b) |x – 1,4| = 2,6}$
$\text{x – 1,4 = 2,6 hoặc x – 1,4 = -2,6}$
$\text{TH1: x – 1,4 = 2,6}$
$\text{ x = 2,6 + 1,4}$
$\text{ x = 4}$
$\text{TH2: x – 1,4 = -2,6}$
$\text{ x = -2,6 + 1,4}$
$\text{ x = -1,2}$
$\text{Vậy x ∈ {4; -1,2}}$
`a)1/4-(x+1/2)=3/5`
`→x+1/2=1/4-3/5`
`→x+1/2=-7/20`
`→x=-7/20-1/2`
`→x=-17/20`
Vậy `x=-17/20`
`b)|x-1,4|=2,6`
`→` \(\left[ \begin{array}{l}x-1,4=2,6\\x-1,4=-2,6\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=4\\x=-1,2\end{array} \right.\)
Vậy `x∈{4;-1,2}`