Toán a) 2|1/2x – 1/3|- 3/2 = 1/4 b) 4/5 – 1/2x = 1/10 19/10/2021 By Eva a) 2|1/2x – 1/3|- 3/2 = 1/4 b) 4/5 – 1/2x = 1/10
a) `2|1/2 x – 1/3|- 3/2 = 1/4` `→2|1/2 x-1/3|=7/4` `→|1/2 x-1/3|=7/8` `→` \(\left[ \begin{array}{l}\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{7}{8}\\\dfrac{1}{2}x-\dfrac{1}{3}=-\dfrac{7}{8}\end{array} \right.\) `→` \(\left[ \begin{array}{l}\dfrac{1}{2}x=\dfrac{29}{24}\\\dfrac{1}{2}x=-\dfrac{13}{24}\end{array} \right.\) `→` \(\left[ \begin{array}{l}x=\dfrac{29}{12}\\x=-\dfrac{13}{12}\end{array} \right.\) Vậy `x∈{29/12;-13/12}` b) `4/5-1/2x=1/10` `→1/2x=4/5-1/10` `→1/2x=7/10` `→x=7/5` Vậy `x=7/5` Trả lời
a 2|1/2x – 1/3| – 3/2 = 1/4 2|1/2x – 1/3| = 7/4 |1/2x- 1/3| = 7/8 => 1/2x- 1/3 = 7/8 => 1/2x= 29/24 => x= 29/12 => 1/2x – 1/3 = -7/8=> 1/2x = 13/24=> x= 13/12 b. 4/5 -1/2x= 1/10 1/2x = 7/10 x = 7/5 Trả lời
a)
`2|1/2 x – 1/3|- 3/2 = 1/4`
`→2|1/2 x-1/3|=7/4`
`→|1/2 x-1/3|=7/8`
`→` \(\left[ \begin{array}{l}\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{7}{8}\\\dfrac{1}{2}x-\dfrac{1}{3}=-\dfrac{7}{8}\end{array} \right.\)
`→` \(\left[ \begin{array}{l}\dfrac{1}{2}x=\dfrac{29}{24}\\\dfrac{1}{2}x=-\dfrac{13}{24}\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=\dfrac{29}{12}\\x=-\dfrac{13}{12}\end{array} \right.\)
Vậy `x∈{29/12;-13/12}`
b)
`4/5-1/2x=1/10`
`→1/2x=4/5-1/10`
`→1/2x=7/10`
`→x=7/5`
Vậy `x=7/5`
a 2|1/2x – 1/3| – 3/2 = 1/4
2|1/2x – 1/3| = 7/4
|1/2x- 1/3| = 7/8
=> 1/2x- 1/3 = 7/8 => 1/2x= 29/24 => x= 29/12
=> 1/2x – 1/3 = -7/8=> 1/2x = 13/24=> x= 13/12
b. 4/5 -1/2x= 1/10
1/2x = 7/10
x = 7/5