A, 2x(x-1)=3x-3 B.x2-6x=0 C.x(x-3)-x2+5=0 D. 3x+2(5-x)=0 E. (X+2)2=(x-2)(x+2) Giúp e vs mai em thi r 05/08/2021 Bởi Abigail A, 2x(x-1)=3x-3 B.x2-6x=0 C.x(x-3)-x2+5=0 D. 3x+2(5-x)=0 E. (X+2)2=(x-2)(x+2) Giúp e vs mai em thi r
a, 2x(x-1)=3x-3 ⇒2x(x-1)-3x+3=0 ⇒2x(x-1)-3(x-1)=0 ⇒(x-1)(2x-3)=0 ⇒\(\left[ \begin{array}{l}x-1=0\\2x-3=0\end{array} \right.\) =>\(\left[ \begin{array}{l}x=1\\2x=3\end{array} \right.\) =>\(\left[ \begin{array}{l}x=1\\x=3/2\end{array} \right.\) Vậy x=1, x=3/2 b, x²-6x=0 ⇒x(x-6)=0 ⇒\(\left[ \begin{array}{l}x=0\\x-6=0\end{array} \right.\) =>\(\left[ \begin{array}{l}x=0\\x=6\end{array} \right.\) Vậy x=0, x=6 c, x(x-3)-x²+3=0 ⇒x(x-3)-x(x-3)=0 ⇒(x-3)(x-x)=0 ⇒(x-3).0=0 ⇒x-3=0 ⇒x=3 (Học tốt nhé!) Bình luận
a, 2x(x-1)=3x-3
⇒2x(x-1)-3x+3=0
⇒2x(x-1)-3(x-1)=0
⇒(x-1)(2x-3)=0
⇒\(\left[ \begin{array}{l}x-1=0\\2x-3=0\end{array} \right.\) =>\(\left[ \begin{array}{l}x=1\\2x=3\end{array} \right.\) =>\(\left[ \begin{array}{l}x=1\\x=3/2\end{array} \right.\)
Vậy x=1, x=3/2
b, x²-6x=0
⇒x(x-6)=0
⇒\(\left[ \begin{array}{l}x=0\\x-6=0\end{array} \right.\) =>\(\left[ \begin{array}{l}x=0\\x=6\end{array} \right.\)
Vậy x=0, x=6
c, x(x-3)-x²+3=0
⇒x(x-3)-x(x-3)=0
⇒(x-3)(x-x)=0
⇒(x-3).0=0
⇒x-3=0
⇒x=3
(Học tốt nhé!)