a) (2x-1)(5x^2-4x+3) b) x (1-x) (2-2x)-(x-5) (x+4) tinh gia tri bieu thuc

a) (2x-1)(5x^2-4x+3)
b) x (1-x) (2-2x)-(x-5) (x+4)
tinh gia tri bieu thuc

0 bình luận về “a) (2x-1)(5x^2-4x+3) b) x (1-x) (2-2x)-(x-5) (x+4) tinh gia tri bieu thuc”

  1. `a)`

    `(2x-1)(5x^2-4x+3)`

    `=2x.(5x^2-4x+3)-1.(5x^2-4x+3)`

    `=10x^3-8x^2+6x-5x^2+4x-3`

    `=10x^3-(8x^2+5x^2)+(6x+4x)-3`

    `=10x^3-13x^2+10x-3`

    `b)`

    `x(1-x)(2-2x)-(x+5)(x+4)`

    `=x(2-2x-2x+2x^2)-(x^2+4x+5x+20)`

    `=x(2x^2-4x+2)-(x^2+9x+20)`

    `=2x^3-4x^2+2x-x^2-9x-20`

    `=2x^3-(4x^2+x^2)+(2x-9x)-20`

    `=2x^3-5x^2-7x-20`

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  2. (2x-1)(-4x+3)

    =10-13+10x-3

    x(1−x)(2−2x)−(x+5)(x+4)x(1-x)(2-2x)-(x+5)(x+4)

    =x(2−2x−2x+2$x^{2}$)−($x^{2}$+4x+5x+20)

    =x(2$x^{2}$−4x+2)−($x^{2}$+9x+20)

    =2$x^{3}$−4$x^{2}$+2x−$x^{2}$−9x−20

    =2$x^{3}$−(4$x^{2}$+$x^{2}$)+(2x−9x)−20

    =2$x^{3}$−5$x^{2}$−7x−20

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