a) (2x-1)(5x^2-4x+3) b) x (1-x) (2-2x)-(x-5) (x+4) tinh gia tri bieu thuc 14/07/2021 Bởi aikhanh a) (2x-1)(5x^2-4x+3) b) x (1-x) (2-2x)-(x-5) (x+4) tinh gia tri bieu thuc
`a)` `(2x-1)(5x^2-4x+3)` `=2x.(5x^2-4x+3)-1.(5x^2-4x+3)` `=10x^3-8x^2+6x-5x^2+4x-3` `=10x^3-(8x^2+5x^2)+(6x+4x)-3` `=10x^3-13x^2+10x-3` `b)` `x(1-x)(2-2x)-(x+5)(x+4)` `=x(2-2x-2x+2x^2)-(x^2+4x+5x+20)` `=x(2x^2-4x+2)-(x^2+9x+20)` `=2x^3-4x^2+2x-x^2-9x-20` `=2x^3-(4x^2+x^2)+(2x-9x)-20` `=2x^3-5x^2-7x-20` Bình luận
(2x−1)(5$x^{2}$ −4x+3)(2x-1)(5$x^{2}$-4x+3) =2x.(5$x^{2}$−4x+3)−1.(5$x^{2}$−4x+3) =10$x^{3}$−8$x^{2}$+6x−5$x^{2}$+4x−3 =10$x^{3}$−(8$x^{2}$+5$x^{2}$)+(6x+4x)−3 =10$x^{3}$-13$x^{2}$+10x-3 b) x(1−x)(2−2x)−(x+5)(x+4)x(1-x)(2-2x)-(x+5)(x+4) =x(2−2x−2x+2$x^{2}$)−($x^{2}$+4x+5x+20) =x(2$x^{2}$−4x+2)−($x^{2}$+9x+20) =2$x^{3}$−4$x^{2}$+2x−$x^{2}$−9x−20 =2$x^{3}$−(4$x^{2}$+$x^{2}$)+(2x−9x)−20 =2$x^{3}$−5$x^{2}$−7x−20 Bình luận
`a)`
`(2x-1)(5x^2-4x+3)`
`=2x.(5x^2-4x+3)-1.(5x^2-4x+3)`
`=10x^3-8x^2+6x-5x^2+4x-3`
`=10x^3-(8x^2+5x^2)+(6x+4x)-3`
`=10x^3-13x^2+10x-3`
`b)`
`x(1-x)(2-2x)-(x+5)(x+4)`
`=x(2-2x-2x+2x^2)-(x^2+4x+5x+20)`
`=x(2x^2-4x+2)-(x^2+9x+20)`
`=2x^3-4x^2+2x-x^2-9x-20`
`=2x^3-(4x^2+x^2)+(2x-9x)-20`
`=2x^3-5x^2-7x-20`
(2x−1)(5$x^{2}$ −4x+3)(2x-1)(5$x^{2}$-4x+3)
=2x.(5$x^{2}$−4x+3)−1.(5$x^{2}$−4x+3)
=10$x^{3}$−8$x^{2}$+6x−5$x^{2}$+4x−3
=10$x^{3}$−(8$x^{2}$+5$x^{2}$)+(6x+4x)−3
=10$x^{3}$-13$x^{2}$+10x-3
b)
x(1−x)(2−2x)−(x+5)(x+4)x(1-x)(2-2x)-(x+5)(x+4)
=x(2−2x−2x+2$x^{2}$)−($x^{2}$+4x+5x+20)
=x(2$x^{2}$−4x+2)−($x^{2}$+9x+20)
=2$x^{3}$−4$x^{2}$+2x−$x^{2}$−9x−20
=2$x^{3}$−(4$x^{2}$+$x^{2}$)+(2x−9x)−20
=2$x^{3}$−5$x^{2}$−7x−20