a = 2/1.5+3/5.11+4/11.19+5/19.29+6/29.41 tính giá trị biểu thức 27/07/2021 Bởi Ruby a = 2/1.5+3/5.11+4/11.19+5/19.29+6/29.41 tính giá trị biểu thức
Đáp án: `A = 2/(1 × 5) + 3/(5 × 11) + 4/(11 × 19) + 5/(19 × 29) + 6/(29 × 41)` `⇔ 2 × A = 2 × (2/(1 × 5) + 3/(5 × 11) + 4/(11 × 19) + 5/(19 × 29) + 6/(29 × 41) )` `⇔ 2 × A = 4/(1 × 5) + 6/(5 × 11) + 8/(11 × 19) + 10/(19 × 29) + 12/(29 × 41)` `⇔ 2 × A = 1 – 1/5 + 1/5 – 1/11 + 1/11 – 1/9 + 1/19 – 1/29 + 1/29 – 1/41` `⇔ 2 × A = 1 + (- 1/5 + 1/5 – 1/11 + 1/11 – 1/9 + 1/19 – 1/29 + 1/29) – 1/41` `⇔ 2 × A = 1 – 1/41` `⇔ 2 × A = 40/41` `⇔ A = 40/41 ÷ 2` `⇔ A=20/41` `text{Vậy}` `A = 20/41` Bình luận
Đáp án: `A=20/41` Giải thích các bước giải: `A=2/1.5+3/5.11+4/11.19+5/19.29+6/29.41` `2A=(2^2)/1.5+(2.3)/5.11+(2.4)/11.19+(5.2)/19.29+(2.6)/29.41` `2A=4/1.5+6/5.11+8/11.19+10/19.29+12/29.41` `2A=1-1/5+1/5-1/11+1/11-1/19+1/19-1/29+1/29-1/41` `2A=1-1/41` `2A=40/41` `A=40/41:2` `A=20/41` Vậy `A=20/41`. Bình luận
Đáp án:
`A = 2/(1 × 5) + 3/(5 × 11) + 4/(11 × 19) + 5/(19 × 29) + 6/(29 × 41)`
`⇔ 2 × A = 2 × (2/(1 × 5) + 3/(5 × 11) + 4/(11 × 19) + 5/(19 × 29) + 6/(29 × 41) )`
`⇔ 2 × A = 4/(1 × 5) + 6/(5 × 11) + 8/(11 × 19) + 10/(19 × 29) + 12/(29 × 41)`
`⇔ 2 × A = 1 – 1/5 + 1/5 – 1/11 + 1/11 – 1/9 + 1/19 – 1/29 + 1/29 – 1/41`
`⇔ 2 × A = 1 + (- 1/5 + 1/5 – 1/11 + 1/11 – 1/9 + 1/19 – 1/29 + 1/29) – 1/41`
`⇔ 2 × A = 1 – 1/41`
`⇔ 2 × A = 40/41`
`⇔ A = 40/41 ÷ 2`
`⇔ A=20/41`
`text{Vậy}` `A = 20/41`
Đáp án:
`A=20/41`
Giải thích các bước giải:
`A=2/1.5+3/5.11+4/11.19+5/19.29+6/29.41`
`2A=(2^2)/1.5+(2.3)/5.11+(2.4)/11.19+(5.2)/19.29+(2.6)/29.41`
`2A=4/1.5+6/5.11+8/11.19+10/19.29+12/29.41`
`2A=1-1/5+1/5-1/11+1/11-1/19+1/19-1/29+1/29-1/41`
`2A=1-1/41`
`2A=40/41`
`A=40/41:2`
`A=20/41`
Vậy `A=20/41`.