Toán a)2/3x-1/2x=5/2 b)1/3x+2/5( x-1)=0 c)(2x-3)(6-2x)=0 d)(3x-1)(-1/2x+5)=0 14/10/2021 By Ximena a)2/3x-1/2x=5/2 b)1/3x+2/5( x-1)=0 c)(2x-3)(6-2x)=0 d)(3x-1)(-1/2x+5)=0
a)2/3x-1/2x=5/2 <=> x(2/3- 1/2)= 5/2 <=>1/6x= 5/2 <=>x= 15 vậy x= 15 b, 1/3x+2/5( x-1)=0 <=> 1/3x+ 2/5x- 2/5=0 <=> x(1/2+2/5)= 2/5 <=> 9/10x= 2/5 <=> x=4/9 Vậy x=4/9 c, (2x-3)(6-2x)=0 TH1: 2x-3=0 <=> 2x=3 <=> x=3/2 TH2: 6-2x=0 <=> 2x=6 <=>x=3 Vậy x thuộc {3/2; 3} d, (3x-1)(-1/2x+5)=0 TH1: 3x-1=0 <=> 3x=1 <=> x=1/3 TH2: -1/2x+5=0 <=> 1/2x=5 <=>x=10 Vậy x thuộc {1/3; 10} Trả lời
a)2/3x-1/2x=5/2
<=> x(2/3- 1/2)= 5/2
<=>1/6x= 5/2
<=>x= 15
vậy x= 15
b, 1/3x+2/5( x-1)=0
<=> 1/3x+ 2/5x- 2/5=0
<=> x(1/2+2/5)= 2/5
<=> 9/10x= 2/5
<=> x=4/9
Vậy x=4/9
c, (2x-3)(6-2x)=0
TH1: 2x-3=0
<=> 2x=3
<=> x=3/2
TH2: 6-2x=0
<=> 2x=6
<=>x=3
Vậy x thuộc {3/2; 3}
d, (3x-1)(-1/2x+5)=0
TH1: 3x-1=0
<=> 3x=1
<=> x=1/3
TH2: -1/2x+5=0
<=> 1/2x=5
<=>x=10
Vậy x thuộc {1/3; 10}
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