a) x/2(x-3) + x/2x+2 = 2x/ (x+1) (x-3) b) x+25/2x^2-50 – x+5/x^2-5x = 5-x/2x^2+10x c) 3/x^2+x-2 – 1/x-1 = -7/x+2 d) 6/x-1 – 4/x-3 = 8/(x-1)(3-x) e) 1/

0 bình luận về “a) x/2(x-3) + x/2x+2 = 2x/ (x+1) (x-3) b) x+25/2x^2-50 – x+5/x^2-5x = 5-x/2x^2+10x c) 3/x^2+x-2 – 1/x-1 = -7/x+2 d) 6/x-1 – 4/x-3 = 8/(x-1)(3-x) e) 1/”

1. `x/(2(x-3)) + x/(2x+2) = (2x)/ ((x+1) (x-3))`

   `<=>x(x+1)+x(x-3)=4x`

   `<=>2x^2-6x=0`

   `<=>x=0` hoặc `x=3(ktm)`

   Vậy ……..

   `( x+25)/(2x^2-50) – (x+5)/(x^2-5x) = (5-x)/(2x^2+10x)`

   `<=>-x^2+5x-50=10x-25-x^2`

   `<=>5x=-25`

   `<=>x=-5(l)`

   `3/(x^2+x-2 )- 1/(x-1) = -7/(x+2)`

   `<=>3-x-2=-7(x-1)`

   `<=>x=1(l)`

   `6/(x-1) – 4/(x-3) = 8/((x-1)(3-x))`

   `<=>20x-2x^2-42=8x-24`

   `<=>(x-3)^2=0`

   `<=>x=3(l)`

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